如何使用AJAX PHP和mysqli的,而無需使用任何按鈕,開始讀數據庫 數據Ajax功能? 當我向表中添加一行時,我希望在頁面上顯示信息而不加載/刷新頁面或單擊按鈕。我可以這樣做嗎?實現使用的mysqli和PHP和jQuery
而這個信息將出現如下圖所示
PHP代碼
<?php
if (isset($_GET['id'])) {
$id = intval($_GET['id']);
$date = date("l jS \of F Y");
$query = mysqli_query($conn, "select * from tbl_dailyprogress where db_activityid='$id' and db_d='1'")or die(mysqli_error($conn));
$count = mysqli_num_rows($query);
if ($count != 0) {
echo"<table class='ol-md-12 table-bordered table-striped table-condensed cf table-bordered' id='alternatecolor'>";
echo"<thead class='cf'>";
echo"<tr>";
echo" <th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Date</th>
<th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Notes</th>
<th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Progress %</th>
";
echo"</tr></thead><tbody>";
while ($row = mysqli_fetch_array($query)) {
$idp = $row['db_id'];
$date = $row['db_date'];
$note = $row['db_note'];
$progress = $row['db_progress'];
echo"<tr>";
echo"<td data-title='Date'>";
echo $date;
echo"</td>";
echo"<td data-title='Note'>";
echo $note;
echo"</td>";
echo"<td data-title='Progress %'>";
echo'
<div class="progress">
<div class="progress-bar" role="progressbar" aria-valuenow="70" aria-valuemin="0" aria-valuemax="100" style="width:' . $progress . '%">
' . $progress . '%
</div>
</div>';
echo"</td>";
}
echo"</tr></tbody>";
echo"</table>";
echo"<br/>";
}?>
使用jQuery阿賈克斯 – Deep
我不知道你的意思。你想要在用戶添加行時自動添加行?如果用戶在瀏覽器中添加一行,爲什麼需要查詢數據庫獲取更多行?您已在瀏覽器中擁有新行。 – BeetleJuice
我該怎麼辦,我沒有與經驗,如果你能幫助我PLZ – user3018000