服務器端驗證錯誤不顯示。用戶轉到標題位置

Question

所以我有我認爲是經過驗證和消毒的表單。當註冊商點擊提交按鈕時，它會將其帶到「標題」位置。即使註冊服務商沒有正確完成輸入，它仍然會將註冊服務商發送到「標題」位置。從我所看到的可能是兩件事之一。驗證碼不對，或者我沒有正確顯示錯誤。我將在下面留下我的代碼。

下面的index.php

<php include("php/processuserform.php"); ?> 


    <form method="POST" name="signup" action="php/processuserform.php"> 

    <input id="firstname" onkeyup="validateFirstName()" placeholder="First Name" type="text" 
    value="<?php echo $valid_firstname; ?>" /><?php echo $error_firstname; ?><label 
    id="firstnameprompt"> 
    </label> 

    <br><br> 

    <input id="lastname" onkeyup="validateLastName()" placeholder="Last Name" type="text" value="<?php 
    echo $valid_lastname; ?>" /><?php echo $error_lastname; ?><label id="lastnameprompt"></label> 

    <br><br> 


    <input id="Email" onkeyup="validateEmail()" placeholder="Email" type="text" value="<?php echo 
    $valid_email; ?>" /><label id="Emailprompt"><?php echo $error_email; ?></label> 

    <br /><br /> 

    <input id="Password" onkeyup="validatePassword()" placeholder="Create Password" type="password" 
    value="<?php echo $valid_password; ?>" /><label id="Passwordprompt"><?php echo $error_password; ?> 
    </label> 


    <br /><br /> 


<strong>Male</strong><input id="Gender" type="radio" name="sex" value="m"> 
<strong>Female</strong><input id="Gender" type="radio" name="sex" value="f"> 
<?php echo $error_gender; ?> 

<br /><br /> 

Click "Submit" if you agree to <a href="#">"Terms And Conditions"</a> 
<br> 
<input id="submit" onclick="return validateUserRegistration()" value="Submit" type="submit" 
name="submit"/><label id="submitprompt"></label> 

現在是processuserform.php

<?php 
if($_POST) 
{ 
$first_name = $_POST['firstname']; 
$last_name = $_POST['lastname']; 
$email = $_POST['Email']; 
$pw = $_POST['Password']; 
$gender = $_POST['Gender']; 
$data = array("$first_name","$last_name","$email","$pw",$gender); 

function test_input($data) 
{ 
$data = trim($data); 
$data = stripslashes($data); 
$data = htmlspecialchars($data); 
return $data; 
} 
//========================================== 
// FirstName 
if (preg_match('/^[a-zA-Z ]*$/',$first_name)) 
{ 
$valid_firstname=$first_name; 
} 
else 
{ 
$error_firstname='Enter First Name.'; 
} 


//========================================== 
// Last Name 
if (preg_match('/^[a-zA-Z ]*$/',$last_name)) 
{ 
$valid_lastname=$last_name; 
} 
else 
{ 
$error_lastname='Enter Last Name.'; 
} 

//========================================== 
// Email 
if (preg_match('/^[a-zA-Z0-9._-]+@[a-zA-Z0-9._-]+\.([a-zA-Z]{2,4})$/', $email)) 
{ 
$valid_email=$email; 
} 
else 
{ 
$error_email='Enter valid Email.'; 
} 

//========================================== 
// Password min 6 char max 20 char 
if (preg_match('/^[A-Za-z0-9!@#$%^&*()_]{6,20}$/',$pw)) 
{ 
$valid_password=$pw; 
} 
else 
{ 
$error_password='Enter valid Password min 6 Chars.'; 
} 

//========================================== 
// Gender 

if ($gender==m) 
{ 
$valid_gender==$gender; 
} 
if ($gender==f) 
{ 
$valid_gender==$gender; 
} 
else 
{ 
$error_gender='Select Gender'; 
} 

//========================================= 
$hostname="this is correct"; 
$username="this is correc"; 
$password="this is correc"; 
$dbname="this is correc"; 

    $db_conx = mysqli_connect($hostname, $username, $password) OR DIE ("Unable to 
    connect to database! Please try again later."); 

    if(mysqli_connect_errno()){ 
    echo mysqli_connect_error(); 
    exit(); 
    } 

    $select = mysqli_select_db($db_conx,$dbname); 


if((strlen($valid_firstname)>0)&&(strlen($valid_lastname)>0) 
&&(strlen($valid_email)>0)&&(strlen($valid_password)>0) && $valid_gender==m||f) 
{ 
    mysqli_query($db_conx,"INSERT INTO users (firstname, lastname, email, password, gender) 
    VALUES ('$first_name', '$last_name', '$email', '$pw', '$gender')"); 
    mysqli_close($db_conx); 

header("Location: pages/profile.php"); 
} 
else{ } 

} 
?> 

Answer 1

$valid_gender==m||f不是PHP條件下有效的語法。

• m和f不是字符串，你會需要一個表單輸入（串）比較它們
• 的或條件不以這種方式工作

在PHP中，這始終打印「這是真的」：

$valid_gender = "s"; 
if(0 && $valid_gender==m||f){ 
    echo "it's true"; 
} 

這是相同的話說：「如果valid_gender等於M或f爲真。」

這讓您的病情總是等同於true

試試這個：

if($valid_gender == "m" || $valid_gender == "f"){ 

甚至

if(in_array($valid_gender,array("m","f"))){