您好在桌面單元格中使用UIStepper。當UIStepper值改變,我必須顯示錶視圖cell..Here在標籤值的代碼iOS中的UIStepper UILabel
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UILabel *lblQuantityValue = [[UILabel alloc] initWithFrame:CGRectMake(140, 410, 50, 30)];
lblQuantityValue.text = @"1";
lblQuantityValue.tag = indexPath.section;
lblQuantityValue.backgroundColor = [UIColor clearColor];
[[lblQuantityValue layer] setCornerRadius:5];
[[lblQuantityValue layer] setMasksToBounds:YES];
[[lblQuantityValue layer] setBorderWidth:1.0f];
[[lblQuantityValue layer] setBorderColor:[[UIColor orangeColor]CGColor]];
[cell addSubview:lblQuantityValue];
UIStepper *stepper = [[UIStepper alloc] initWithFrame:CGRectMake(200, 410, 50, 30)];
[stepper addTarget:self action:@selector(stepper_ValueChanged:) for ControlEvents:UIControlEventValueChanged];
stepper.tag = indexPath.row;
stepper.minimumValue = 1;
stepper.maximumValue = 10;
[cell addSubview:stepper];
}
stepper_ValueChanged方法如下
-(void)stepper_ValueChanged:(UIStepper*)sender
{
UILabel *lblQuantityValue = (UILabel*)[self.view viewWithTag:sender.tag];
int value2 = [sender value];
lblQuantityValue.text = [NSString stringWithFormat:@"%d", value2];
}
我收到崩潰報告如下
-[UIView setText:]: unrecognized selector sent to instance 0x111e10640
2014-02-26 11:22:24.159 Hyderabad Bazar[2115:a0b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIView setText:]: unrecognized selector sent to instance 0x111e10640'
*** First throw call stack:
(
0 CoreFoundation 0x0000000101ce3795 __exceptionPreprocess + 165
1 libobjc.A.dylib 0x00000001019bf991 objc_exception_throw + 43
2 CoreFoundation 0x0000000101d74bad -[NSObject(NSObject) doesNotRecognizeSelector:] + 205
3 CoreFoundation 0x0000000101cd509d ___forwarding___ + 973
4 CoreFoundation 0x0000000101cd4c48 _CF_forwarding_prep_0 + 120
5 Hyderabad Bazar 0x00000001000202a6 -[CartViewController stepper_ValueChanged:] + 390
6 UIKit 0x0000000100628a8a -[UIApplication sendAction:to:from:forEvent:] + 104
7 UIKit 0x0000000100628a20 -[UIApplication sendAction:toTarget:fromSender:forEvent:] + 17
8 UIKit 0x00000001006fc91c -[UIControl _sendActionsForEvents:withEvent:] + 203
9 UIKit 0x0000000100a895d7 -[UIStepper _updateCount:] + 338
10 UIKit 0x0000000100a89346 -[UIStepper endTrackingWithTouch:withEvent:] + 32
11 UIKit 0x00000001006fbe52 -[UIControl touchesEnded:withEvent:] + 472
12 UIKit 0x000000010092cc0d _UIGestureRecognizerUpdate + 5149
13 UIKit 0x000000010065d2e5 -[UIWindow _sendGesturesForEvent:] + 928
14 UIKit 0x000000010065dfa5 -[UIWindow sendEvent:] + 910
15 UIKit 0x0000000100637962 -[UIApplication sendEvent:] + 211
16 UIKit 0x000000010062579f _UIApplicationHandleEventQueue + 9549
17 CoreFoundation 0x0000000101c72e61 __CFRUNLOOP_IS_CALLING_OUT_TO_A_SOURCE0_PERFORM_FUNCTION__ + 17
18 CoreFoundation 0x0000000101c72732 __CFRunLoopDoSources0 + 242
19 CoreFoundation 0x0000000101c8e5bf __CFRunLoopRun + 767
20 CoreFoundation 0x0000000101c8ded3 CFRunLoopRunSpecific + 467
21 GraphicsServices 0x000000010408a3a4 GSEventRunModal + 161
22 UIKit 0x0000000100627a63 UIApplicationMain + 1010
23 Hyderabad Bazar 0x00000001000274e3 main + 115
24 libdyld.dylib 0x00000001028067e1 start + 0
請幫我
同意DANH,你推測viewWithTag是一個UILabel,但沒有保證,它實際上是。在將它作爲標籤對待之前調用([lblQuantityValue idKindOfClass:[UILabel class])可能會非常有幫助。 –
另外一個潛在的基於標籤的災難是你如何分配標籤。使用該部分作爲標籤的標籤,將該行作爲步進器的標籤可以保證標籤碰撞。如果您要使用標籤,那麼您有責任確保所有標籤對於調用視圖和所有子視圖都是唯一的,一直沿着視圖層次結構。 –