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我一直在研究散列表。我不斷收到分段錯誤。我一直在試圖調試它,但它總是指向addOrder
有分段錯誤。即使在更改代碼時也會出現分段錯誤
我哪裏錯了?還有什麼其他方式可以實現我的代碼來檢查任何角落情況?
struct order
{
int id;
char side;
int quantity;
double price;
};
struct onode
{
struct order* data;
struct onode* next;
struct onode* prev;
};
/*
* Create a new instance of struct hashStorage and return it. It sets the size of the
* table to be of length "size" which will be the number of the entries in the hash. It takes also an
* argument to specify the format of the order printed to an output stream. If myHash parameter
* is NULL then this means that the hash should be a linked list. When myHash is NULL the size
* parameter should be ignored.
*/
struct hashStorage* createHash(int size, int (*myHash)(int),void(*printOrder)(struct order *, FILE *))
{
struct hashStorage* hashList = (struct hashStorage*) malloc(sizeof(struct hashStorage));
if(myHash == NULL)
{
hashList->size = 1;
hashList->table = (struct onode**) calloc(1, sizeof(struct onode*));
}
if(myHash != NULL)
{
hashList->table = (struct onode**) calloc(size, sizeof(struct onode*));
hashList->size = size;
}
hashList->funcHash = myHash;
hashList->printItem = printOrder;
return hashList;
}
/*
* Add an order to the hash structure. Remember that you should copy the data before
* adding it to the hash as data can be modified (hint: look at newNode in list).
* It returns the new onode.
*/
struct onode* addOrder(struct hashStorage* hash, struct order* data)
{
int addIndex;
struct onode* dataList = newNode(data);
addIndex = hash -> funcHash(getOrderId(data));
pushNode(&(hash->table[addIndex]), dataList);
return dataList;
}
你知道什麼特定的線路導致分段故障嗎? – nairdaen 2013-03-19 05:27:12
fyi你錯過了/在第一個評論 – 2013-03-19 05:28:29
沒有它只是說addOrder argv有垃圾值 – Maddy 2013-03-19 05:28:59