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我正在使用以下php腳本在我的網站上顯示一個隨機圖像,它的工作原理很好,除了它會抓取圖像,我不希望它抓住所以我想添加一個檢查腳本,以便它只會抓取圖像,如果它以字母「TN-」開頭,但我不是一個PHP編碼器,所以我想我會問這裏的專家一些幫助。特定文件名的php隨機圖像腳本
<?php
// files to search for
$extList = array();
$extList['gif'] = 'image/gif';
$extList['jpg'] = 'image/jpeg';
$extList['jpeg'] = 'image/jpeg';
$extList['png'] = 'image/png';
// set to specific image if needed
// null will result in a random image
$img = null;
// path to the directory you want to scan
$directory = './';
if (substr($directory,-1) != '/') {
$directory = $directory.'/';
}
// if img is set, show it
if (isset($_GET['img'])) {
$imageInfo = pathinfo($_GET['img']);
if (
isset($extList[ strtolower($imageInfo['extension']) ]) &&
file_exists($directory.$imageInfo['basename'])
) {
$img = $directory.$imageInfo['basename'];
}
}
// if img isnt set, grab a random
else {
//cycle through directory and subfolders
$it = new RecursiveDirectoryIterator("$directory");
foreach(new RecursiveIteratorIterator($it) as $file)
{
$file_info = pathinfo($file);
if (
isset($extList[ strtolower($file_info['extension']) ])
) {
$items[] = $file;
}
}
sort($items);
// get the random image
if (count($items) > 0) {
$imageNumber = time() % count($items);
$img = $directory.$items[$imageNumber];
}
}
// if img isnt null, display it
if ($img!=null) {
$imageInfo = pathinfo($img);
$contentType = 'Content-type: '.$extList[ $imageInfo['extension'] ];
header ($contentType);
readfile($img);
}
// else, try to create one or give error
else {
if (function_exists('imagecreate')) {
header ("Content-type: image/png");
$im = @imagecreate (100, 100)
or die ("Cannot initialize new GD image stream");
$background_color = imagecolorallocate ($im, 255, 255, 255);
$text_color = imagecolorallocate ($im, 0,0,0);
imagestring ($im, 2, 5, 5, "IMAGE ERROR", $text_color);
imagepng ($im);
imagedestroy($im);
}
}
?>
謝謝,現在的偉大工程。非常感激。 – nosx