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我使用下面的JavaScript與TreeView的節點複選框選擇/取消Functionality.I必須在treeview.parent,子女三個層面和siblings.javascript代碼工作正常,但我需要的兄弟姐妹級別相互依賴地檢查和取消選擇。不影響父母和孩子的檢查/取消選中。有一個PLZ幫助我修改代碼。使用JavaScript與TreeView的節點選擇/取消功能
<script type="text/javascript">
function OnTreeClick(evt) {
var src = window.event != window.undefined ? window.event.srcElement : evt.target
var isChkBoxClick = (src.tagName.toLowerCase() == "input" && src.type == "checkbox");
if (isChkBoxClick) {
var parentTable = GetParentByTagName("table", src);
var nxtSibling = parentTable.nextSibling;
if (nxtSibling && nxtSibling.nodeType == 1)//check if nxt sibling is not null & is an element node
{
if (nxtSibling.tagName.toLowerCase() == "div") //if node has children
{
//check or uncheck children at all levels
CheckUncheckChildren(parentTable.nextSibling, src.checked);
}
}
//check or uncheck parents at all levels
CheckUncheckParents(src, src.checked);
}
}
function CheckUncheckChildren(childContainer, check) {
var childChkBoxes = childContainer.getElementsByTagName("input");
var childChkBoxCount = childChkBoxes.length;
for (var i = 0; i < childChkBoxCount; i++) {
childChkBoxes[i].checked = check;
}
}
function CheckUncheckParents(srcChild, check) {
var parentDiv = GetParentByTagName("div", srcChild);
var parentNodeTable = parentDiv.previousSibling;
if (parentNodeTable) {
var checkUncheckSwitch;
if (check) //checkbox checked
{
checkUncheckSwitch = true;
}
else //checkbox unchecked
{
var isAllSiblingsUnChecked = AreAllSiblingsUnChecked(srcChild);
if (!isAllSiblingsUnChecked)
checkUncheckSwitch = true;
else
checkUncheckSwitch = false;
}
var inpElemsInParentTable = parentNodeTable.getElementsByTagName("input");
if (inpElemsInParentTable.length > 0) {
var parentNodeChkBox = inpElemsInParentTable[0];
parentNodeChkBox.checked = checkUncheckSwitch;
//do the same recursively
CheckUncheckParents(parentNodeChkBox, checkUncheckSwitch);
}
}
}
function AreAllSiblingsUnChecked(chkBox) {
var parentDiv = GetParentByTagName("div", chkBox);
var childCount = parentDiv.childNodes.length;
for (var i = 0; i < childCount; i++) {
if (parentDiv.childNodes[i].nodeType == 1) //check if the child node is an element node
{
if (parentDiv.childNodes[i].tagName.toLowerCase() == "table") {
var prevChkBox = parentDiv.childNodes[i].getElementsByTagName("input")[0];
//if any of sibling nodes are not checked, return false
if (prevChkBox.checked) {
return false;
}
}
}
}
return true;
}
//utility function to get the container of an element by tagname
function GetParentByTagName(parentTagName, childElementObj) {
var parent = childElementObj.parentNode;
while (parent.tagName.toLowerCase() != parentTagName.toLowerCase()) {
parent = parent.parentNode;
}
return parent;
}
</script>
這是一個很大的代碼,沒有解釋的。 –