我似乎無法運行這個簡單的python腳本

-3

however = ["In converse","On the other hand"] 
furthermore = ["To add insult to injury","To add fuel to fire",] 
conclusion = ["To ram the point home","In a nutshell"] 
def prompt(): 
    answer = str(input("Type either 'however','furthermore' or 'conclusion': ")) 
    return answer 
    reply() 

def reply(): 
    if answer == "however": 
     print(however) 
    elif answer == "furthermore": 
     print(furthermore) 
    elif answer == "conclusion": 
     print(conclusion) 
    else: 
     prompt() 
    prompt() 

prompt()

這是怎麼回事？它只是不打印時，我什麼都它只是跳過和犯規打印任何東西我似乎無法運行這個簡單的python腳本

來源

2016-12-24 Yuxin Wei

您的函數調用'reply（）'在return語句之後。那就是問題所在。 –

您需要對函數，參數，參數，範圍，執行順序等進行更多的研究。 – TigerhawkT3

你的解答（）函數類型將不會被調用，因爲你通過返回的答案

退出提示（）函數這是應該如何完成的：

however = ["In converse","On the other hand"] 
furthermore = ["To add insult to injury","To add fuel to fire",] 
conclusion = ["To ram the point home","In a nutshell"] 
def prompt(): 
    answer = str(input("Type either 'however','furthermore' or 'conclusion': ")) 
    reply(answer) 
    return answer 


def reply(answer): 
    if answer == "however": 
     print(however) 
    elif answer == "furthermore": 
     print(furthermore) 
    elif answer == "conclusion": 
     print(conclusion) 
    else: 
     prompt() 
    prompt() 

prompt()

來源

2016-12-24 06:17:18 Hisagr

我似乎無法運行這個簡單的python腳本

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