不,您無法將請求傳遞到user_passes_test
。要理解爲什麼和如何工作的,只是頭部到source:
def user_passes_test(test_func, login_url=None, redirect_field_name=REDIRECT_FIELD_NAME):
"""
Decorator for views that checks that the user passes the given test,
redirecting to the log-in page if necessary. The test should be a callable
that takes the user object and returns True if the user passes.
"""
def decorator(view_func):
@wraps(view_func, assigned=available_attrs(view_func))
def _wrapped_view(request, *args, **kwargs):
if test_func(request.user):
return view_func(request, *args, **kwargs)
path = request.build_absolute_uri()
# If the login url is the same scheme and net location then just
# use the path as the "next" url.
login_scheme, login_netloc = urlparse.urlparse(login_url or
settings.LOGIN_URL)[:2]
current_scheme, current_netloc = urlparse.urlparse(path)[:2]
if ((not login_scheme or login_scheme == current_scheme) and
(not login_netloc or login_netloc == current_netloc)):
path = request.get_full_path()
from django.contrib.auth.views import redirect_to_login
return redirect_to_login(path, login_url, redirect_field_name)
return _wrapped_view
return decorator
這是user_passes_test
裝飾後面的代碼。正如你所看到的,傳遞給裝飾器的測試函數(在你的情況下,lambda u: has_add_permission(u, "project")
)只傳遞一個參數request.user
。現在,編寫你自己的裝飾器(甚至直接拷貝這個代碼並修改它)當然也可以通過request
本身,但是你不能用默認的user_passes_test
實現來完成。
我很好奇,你是怎麼做到的?你有沒有寫自己的裝飾者? – teewuane 2013-12-20 17:00:43
我正在檢查視圖代碼本身內的權限,而不是使用裝飾器。它使我更好地控制視圖邏輯。 – 2013-12-20 18:55:55
這就是我最終做的。謝謝! – teewuane 2013-12-30 20:46:44