查詢邏輯mysql列表比較問題

Question

我比較mysql-listA和listB（這兩個都是視圖）中的兩個電子郵件地址列表。最初，我想查找listA中不在listB中的所有電子郵件地址。我成功地做到了這一點與：

$comparison_query = mysql_query("SELECT DISTINCT email_addresses FROM listA WHERE email_addresses NOT IN (SELECT DISTINCT email_addresses FROM listB) ORDER BY email_addresses"); 

現在，我想找到所有listA的不在數組listB或異常表中的電子郵件地址。我試圖這樣做：

$comparison_query = mysql_query("SELECT email_addresses FROM listA WHERE email_addresses NOT IN (SELECT DISTINCT email_addresses FROM ((SELECT email_addresses FROM listB) UNION (SELECT email_addresses FROM exception))) ORDER BY email_addresses"); 

但是，這是行不通的。任何人都可以看到我要去哪裏嗎？

謝謝！

Answer 1

使用AND代替UNION

mysql_query("SELECT email_addresses FROM listA 
     WHERE email_addresses NOT IN 
     (SELECT DISTINCT email_addresses FROM listB) AND 
     email_addresses NOT IN 
     (SELECT DISTINCT email_addresses FROM exception)) 
     ORDER BY email_addresses"); 

Answer 2

我覺得這樣的事情應該做的伎倆：

SELECT email_addresses FROM listA 
WHERE email_addresses NOT IN 
(SELECT DISTINCT email_addresses FROM FROM listB) 
AND email_addresses NOT IN 
(SELECT email_addresses FROM exception);