我有下面的HTML表單:jQuery的單提交發送兩個請求相同的URL
<form method="post" action="create_user" autocomplete="off" class="user_create_form">
<table class="table table-bordered user">
<tr>
<td class="w20"> Pick Role/Module </td>
<td> <?php echo($db->getRolesCmb()); ?> </td>
</tr>
<tr>
<td> Pick Employee </td>
<td> <?php echo($db->getEmployeeCmb()); ?> </td>
</tr>
<tr>
<td> Choose User ID </td>
<td> <input type="text" name="userid" id="userid" placeholder="Choose User Id for Login"> </td>
</tr>
<tr>
<td> Choose User Password </td>
<td> <input type="password" name="userkey" id="userkey" placeholder="Choose User Password for Login"> </td>
</tr>
<tr>
<td> Confirm User Password </td>
<td> <input type="password" name="cuserkey" id="cuserkey" placeholder="Confirm User Password for Login"> </td>
</tr>
<tr>
<td> Login Status </td>
<td> <input type="radio" name="user_status" id="user_status1" value="1" checked> Enabled
<input type="radio" name="user_status" id="user_status2" value="0"> Disabled
</td>
</tr>
<tr>
<td colspan="2">
<button name="btnSave" id="btnSave" class="btn btn-success">Create User</button>
<span id="msg"></span>
</td>
</tr>
</table>
</form>
我有以下連接到該網頁,其中驗證並提交此表下面的方法.js文件:
// JavaScript Document
"use strict";
$(document).ready(function(e) {
$(".user_create_form").bind("submit",function(event){
event.preventDefault();
if($("#roles").val() == ""){
$("#roles").focus();
$("#msg").html('Please select Module for User').addClass("text-danger");
return false;
}
else if($("#emp_sno").val() == ""){
$("#emp_sno").focus();
$("#msg").html('Please select employee for the login').addClass("text-danger");
return false;
}
else if($.trim($("#userid").val()) == ""){
$("#userid").focus();
$("#msg").html('User id is required here').addClass("text-danger");
return false;
}
else if($.trim($("#userkey").val()) == ""){
$("#userkey").focus();
$("#msg").html('Please choose password for user login').addClass("text-danger");
return false;
}
else if($.trim($("#cuserkey").val()) == ""){
$("#cuserkey").focus();
$("#msg").html('Password confirmation required').addClass("text-danger");
return false;
}
else if($.trim($("#userkey").val()) != $.trim($("#cuserkey").val())){
$("#cuserkey").focus();
$("#msg").html('Password does not match').addClass("text-danger");
return false;
}
else{
// save login information to database
$.ajax({
url: 'myPageUrl.php',
data: new FormData(this),
type:"POST",
cache:false,
contentType:false,
processData:false,
success: function(txt){
$("#msg").html(txt).removeClass('text-danger');
},
error: function(xhr){
$("#msg").html(xhr);
}
});
}
});
});
每一件事情會完美的,但問題是,當我檢查網絡選項卡上的網絡進程的Firefox「螢火蟲」擴展它顯示了兩個請求相同的URL與一個單一的點擊?
現在我很困惑,我做錯了什麼?爲什麼只需點擊一次就可以向同一個網址發送兩個請求?任何幫助是非常讚賞,請
您正在執行一個類的選擇,你可以首先驗證頁面已經渲染後,你只有一個頁面上的