關於簡單的蟒蛇日期計算

Question

我試圖找出什麼時候有人會變成10億秒。用戶在他們出生時輸入。這些值然後轉換爲秒，然後我添加10億秒並轉換回日期。但是，當我輸入特定日期時，python似乎陷入困境。這樣的例子是1993/11/05 00:00:00，python表示用戶將在第0個月交出。 注意我不能使用if/else或datetime。

繼承人我的代碼：

YEARSEC=(12*30*24*3600) 
MONTHSEC=(3600*24*30) 
DAYSEC=(24*3600) 
HOURSEC=3600 
MINUTESEC=60 

year=int(input("Please enter the year in which you were born: ")) 
month=int(input("Please enter the month you were born: "))  
day=int(input("Please enter the day you were born: ")) 
hour=int(input("Please enter the hour you were born: ")) 
minute=int(input("Please enter the minute you were born: ")) 
second=int(input("Please enter the second you were born: ")) 

year_calc=(year*YEARSEC) 
month_calc=(month*MONTHSEC) 
day_calc=(day*DAYSEC) 
hour_calc=(hour*HOURSEC) 
minute_calc=(minute*MINUTESEC) 
s=(1000000000+year_calc+month_calc+day_calc+hour_calc+minute_calc+second) 


year_num=int((s/YEARSEC)) 
s=(s-(year_num*YEARSEC)) 


month_num=int((s/MONTHSEC)) 
s=(s-(month_num*MONTHSEC)) 


day_num=int((s/DAYSEC)) 
s=(s-(DAYSEC*day_num)) 

hour_num=int((s/HOURSEC)) 
s=(s-(HOURSEC*hour_num)) 

minute_num=int((s/MINUTESEC)) 
s=(s-(MINUTESEC*minute_num)) 




print("You will turn 1 000 000 000 seconds old on: %04d/%02d/%02d %02d:%02d:%02d" %(year_num,month_num,day_num,hour_num,minute_num,s)) 

Answer 1

雖然我還沒有測試它總之，我覺得你不能得到日和30日 你應該加1到day_num和month_num原因月份和日期開始從1不是0

print("You will turn 1 000 000 000 seconds old on: %04d/%02d/%02d %02d:%02d:%02d" %(year_num,month_num+1,day_num+1,hour_num,minute_num,s)) 

Answer 2

時間的計算是棘手。例如，幾個月不是全部都有30天。小時，分鐘和秒從0開始編號，但日期和月份從1開始編號，在計算中創建逐個錯誤（提示，請求月份，然後減1，做所有計算，然後添加一次再次顯示時）。你也沒有考慮過閏年。

最好使用內置的工具，如果只是爲了檢查你最終的作業答案，雖然它看起來像老師說的承擔30天的月份; ^）

>>> import datetime 
>>> birthday = datetime.datetime(1993,11,05,0,0,0) 
>>> billion = birthday + datetime.timedelta(seconds=1000000000) 
>>> billion.ctime() 
'Mon Jul 14 01:46:40 2025'