把這個JavaScript和PHP進入codeigniter

Question

<?php 
// This is a code to check the username from a mysql database table 

if(isSet($_POST['username'])) 
{ 
$username = $_POST['username']; 

include("dbconnection.php"); 

$sql_check = mysql_query("SELECT user FROM {$prefix}users WHERE user='$username'"); 

if(mysql_num_rows($sql_check)) 
{ 
echo '<span style="color: red;">The username <b>'.$username.'</b> is already in use.</span>'; 
} 
else 
{ 
echo 'OK'; 
}} 
?> 

這是check.php女巫我可以改變沒有問題與CI一起工作其下面我需要幫助！

<script src="js/jquery.js" type="text/javascript">/script> 
<script type="text/javascript"> 
pic1 = new Image(16, 16); 
pic1.src = "loader.gif"; 

$(document).ready(function(){ 

$("#username").change(function() { 

var usr = $("#username").val(); 

if(usr.length >= 3) 
{ 
$("#status").html('<img align="absmiddle" src="loader.gif" /> Checking availability...'); 

$.ajax({ 
type: "POST", 
url: "check.php", 
data: "username="+ usr, 
success: function(msg){ 

$("#status").ajaxComplete(function(event, request, settings){ 

if(msg == 'OK') 
{ 
$("#username").removeClass('object_error'); // if necessary 
$("#username").addClass("object_ok"); 
$(this).html(' <img align="absmiddle" src="accepted.png" /> '); 
} 
else 
{ 
$("#username").removeClass('object_ok'); // if necessary 
$("#username").addClass("object_error"); 
$(this).html(msg); 
}});}});} 
else 
{ 
$("#status").html('The username should have at least 3 characters.'); 
$("#username").removeClass('object_ok'); // if necessary 
$("#username").addClass("object_error"); 
}});}); 

//--> 

</script> 

我明白什麼最該憑證在做什麼，我可以使其在正常工作，PHP，但我使用的代碼ignighter。如果我正在閱讀它，我應該只需要更改行url：「check.php」，當然，原始的PHP可以任何人指向我在這個正確的方向嗎？

Answer 1

請通過以下網址

• http://ellislab.com/forums/viewthread/184474/#872346