斯卡拉：正則表達式模式匹配

我有以下的輸入字符串斯卡拉：正則表達式模式匹配

"/horses/[email protected]" 
"/Goats/[email protected]" 
"/CATS/[email protected]"

我想獲得

"horses", "c132", "[email protected]" 
"Goats", "b-01", "[email protected]" 
"CATS", "001", "[email protected]"

我嘗試以下

StandardTokenParsers以下爲輸出

import scala.util.parsing.combinator.syntactical._ 
val p = new StandardTokenParsers { 
lexical.reserved ++= List("/", "?", "XXX=") 
def p = "/" ~ opt(ident) ~ "/" ~ opt(ident) ~ "?" ~ "XXX=" ~ opt(ident) 
} 
p: scala.util.parsing.combinator.syntactical.StandardTokenParsers{def p: this.Parser[this.~[this.~[this.~[String,Option[String]],String],Option[String]]]} = [email protected] 

scala> p.p(new p.lexical.Scanner("/horses/[email protected]")) 
warning: there was one feature warning; re-run with -feature for details 
res3: p.ParseResult[p.~[p.~[p.~[String,Option[String]],String],Option[String]]] = 
[1.1] failure: ``/'' expected but ErrorToken(illegal character) found 

/horses/[email protected] 
^

正則表達式

import scala.util.matching.regex 
val p1 = "(/)(.*)(/)(.*)(?)(XXX)(=)(.*)".r 
p1: scala.util.matching.Regex = (/)(.*)(/)(.*)(?)(XXX)(=)(.*) 

scala> val p1(_,animal,_,id,_,_,_,company) = "/horses/[email protected]" 
scala.MatchError: /horses/[email protected] (of class java.lang.String) 
    ... 32 elided

是否有人可以幫忙嗎？謝謝！

來源

2017-12-03 AngryPanda

您的模式看起來像/(desired-group1)/(desired-group2)?XXX=(desired-group3)。

所以，正則表達式將是

scala> val extractionPattern = """(/)(.*)(/)(.*)(\?XXX=)(.*)""".r 
extractionPattern: scala.util.matching.Regex = (/)(.*)(/)(.*)(\?XXX=)(.*)

注 - 逃脫?字符。

它是如何工作的，

Full match `/horses/[email protected]` 
Group 1. `/` 
Group 2. `horses` 
Group 3. `/` 
Group 4. `c132` 
Group 5. `?XXX=` 
Group 6. `[email protected]`

現在，應用它給你的組中的所有的正則表達式匹配

scala> extractionPattern.findAllIn("""/horses/[email protected]""") 
         .matchData.flatMap{m => m.subgroups}.toList 
res15: List[String] = List(/, horses, /, c132, ?XXX=, [email protected])

因爲你只關心第二，第四和護理第六場比賽，只收集那些。

因此該解決方案會是什麼樣子，

scala> extractionPattern.findAllIn("""/horses/[email protected]""") 
         .matchData.map(_.subgroups) 
         .flatMap(matches => Seq(matches(1), matches(3), matches(4))).toList 
res16: List[String] = List(horses, c132, ?XXX=)

當您輸入不匹配正則表達式，你在這裏得到空結果

scala> extractionPattern.findAllIn("""/horses/c132""") 
         .matchData.map(_.subgroups) 
         .flatMap(matches => Seq(matches(1), matches(3), matches(4))).toList 
res17: List[String] = List()

工作正則表達式 - https://regex101.com/r/HuGRls/1/

來源

2017-12-03 02:43:33 prayagupd

斯卡拉：正則表達式模式匹配

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