我試圖添加一個異常,如果用戶沒有輸入任何內容或輸入錯誤的「聯繫人ID」,然後按回車,則會出現錯誤消息&通知用戶未找到ID。任何幫助?在此先感謝:)這裏是我的index.html文件。表單驗證在php/ajax
<html>
<body>
<script language="javascript" type="text/javascript">
function ajaxFunction(e){
var e=e || window.event;
var keycode=e.which || e.keyCode;
if(keycode==13 || (e.target||e.srcElement).value==''){
var http; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
http = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
http = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
http = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
var url = "getagentids.php?param=";
var idValue = document.getElementById("agid").value;
var myRandom = parseInt(Math.random()*99999999); // cache buster
http.open("GET", "getagentids.php?param=" + escape(idValue) + "&rand=" + myRandom, true);
http.onreadystatechange = handleHttpResponse;
http.send(null);
function handleHttpResponse() {
if (http.readyState == 4) {
results = http.responseText.split(",");
document.getElementById('agfn').value = results[0];
document.getElementById('agsal').value = results[1];
document.getElementById('agtel').value = results[2];
document.getElementById('agid').value = results[3];
}
}
}
}
</script>
<form>
<table>
<tr>
<td>Contact ID:</td>
<td><input id="agid" type="text"
name="contactid" onkeyup="ajaxFunction(event)"></td>
</tr>
<tr>
<td>Tel Number:</td>
<td><input id="agtel" type="text"
name="contacttel"></td>
</tr>
<tr>
<td>Name:</td>
<td><input id="agfn" type="text"
name="contactfullname"></td>
</tr>
<tr>
<td>Salutation:</td>
<td><input id="agsal" type="text"
name="contactsalutation"></td>
</tr>
<tr>
<td><input type="reset" value="Clear"></td>
<td></td>
</tr>
</table>
</form>
</body>
</html>
那麼你的問題是什麼,你的代碼不工作? –
@Kanishka tq for reply。我試圖用JS添加異常,但它不適合我。雖然'聯繫人ID'在數據庫中,但彈出窗口出來了。所以我從索引中刪除該代碼。任何想法來驗證ID? – atiquratik
我相信'e.target || e.srcElement'會給你一個TRUE/FALSE值。但是你試圖在代碼中訪問它的value屬性。 –