的Neo4j：通過關係的收集和設置屬性迭代索引

Question

在經典之作（我等。）{...}風格，我想通過一個有序集合迭代 - 僞代碼：

for n,i in nodes 
    set node.weight = i + 1 
end 

可行？

Answer 1

是的，但不是最漂亮的事情：

MATCH ... 
WITH COLLECT(something) AS nodes 
FOREACH(i IN RANGE(0, LENGTH(nodes)) | 
    FOREACH(node IN [nodes[i]] | 
     SET node.weight = i + 1 
))