如何在Windows上爲主叫用戶獲取桌面的絕對路徑

Question

如何爲啓動我的程序的用戶獲取桌面的絕對路徑？

int main() { 
    ofstream myfile; 
    myfile.open ("C:\\Users\\username\\Desktop\\example.txt"); 
    myfile << "Writing this to a file" << endl; 
    myfile.close(); 
} 

Answer 1

編輯：作爲人頭馬勒博建議

我想絕對路徑桌面啓動程序的每一臺計算機？

如果你在Windows下你需要使用API​​ 的SHGetFolderPath功能，點擊here更多信息。

當你得到桌面的路徑時，你將需要將它與你的文件名相結合（附加），生成的路徑將代表位於桌面的文件的完整路徑，有完整的代碼：

#include <iostream> 
#include <Windows.h> 
#include <fstream> 
#include <shlobj.h> // Needed to use the SHGetFolderPath function. 

using namespace std; 

bool GetDesktopfilePath(PTCHAR filePath, PTCHAR fileName) 
{ 
    // Get the full path of the desktop : 
    if (FAILED(SHGetFolderPath(NULL, 
     CSIDL_DESKTOPDIRECTORY | CSIDL_FLAG_CREATE, 
     NULL, 
     SHGFP_TYPE_CURRENT, 
     filePath))) // Store the path of the desktop in filePath. 
     return false; 

    SIZE_T dsktPathSize = lstrlen(filePath); // Get the size of the desktope path. 
    SIZE_T fileNameSize = lstrlen(fileName); // Get the size of the file name. 

    // Appending the fileName to the filePath : 
    memcpy((filePath + dsktPathSize), fileName, (++fileNameSize * sizeof(WCHAR))); 

    return true; 
} 

int main() 
{ 
    ofstream myFile; 

    TCHAR filePath[MAX_PATH];    // To store the path of the file. 
    TCHAR fileName[] = L"\\Textfile.txt"; // The file name must begin with "\\". 

    GetDesktopfilePath(filePath, fileName); // Get the full path of the file situated in the desktop. 

    myFile.open(filePath);     // Opening the file from the generated path. 
    myFile << "Writing this to a file" << endl; 
    myFile.close(); 

    return 0; 
}