需要幫助從JSONArray中提取數據

Question

首先感謝Pentium10的this answer！它讓我更進了一步。

我有在PHP

echo (json_encode($output)); 

產生這個輸出

// linebreaks only for readability, they do not exist in the response 
[["Fitch's Chemist","731 Hay St","(08) 9321 6411"], 
["Ferrara Karaoke Bar","67 Milligan Street","(08) 9481 1909"], 
["Target: Perth","712-720 Hay St","(08) 9327 3700"], 
["C Restaurant","44 St Georges Tce","(08) 9220 8333"], 
["Celona Joe Tailors","146 Murray St","(08) 9325 8274"], 
["Fashion In Colour","Shop 2, 138 Barrack St","(08) 9218 8233"], 
["Mainpeak","858 Hay St","(08) 9322 9044"], 
["Fj Storen Painting Contractors","34 Queen St","(08) 9486 9292"], 
["Financial Pathfinders","Level 4\/81 St Georges Tce","(08) 9213 9699"], 
["Seasons of Perth","37 Pier St","(08) 9325 7655"], 
["David Jones","622 Hay St","(08) 9210 4000"], 
["Pharmacity Chemist Supermart","717 Hay St","(08) 9322 6921"], 
["Austcare","10 Pier St","(08) 9325 9330"], 
["Western Australia","8 Pier St","(08) 9261 6222"], 
["Oceanic Cruises","5 Barrack","(08) 9325 1191"]] 

此輸出填充如下列表陣列產生一個JSONArray;

list(0)["Fitch's Chemist","731 Hay St","(08) 9321 6411"] 
list(1)["Ferrara Karaoke Bar","67 Milligan Street","(08) 9481 1909"] 

我現在需要做的是進一步提取這使「」封閉的數據存儲在三個不同的陣列

try { 
     JSONArray jsonArray = new JSONArray(response); 
     List<String> list = new ArrayList<String>(); 
     for (int i=0; i<jsonArray.length(); i++) { 
      list.add(jsonArray.getString(i)); 
      JSONArray jsonList = new JSONArray(list); 
      BusinessName.add(jsonList.getString(0)); 
      Address.add(jsonList.getString(1)); 
      TelNo.add(jsonList.getString(2)); 
     } 
    } catch (JSONException e) { 
     // TODO Auto-generated catch block 
     e.printStackTrace(); 
     } 

感謝馬丁

Answer 1

編輯：我想你的榜樣，代碼幾乎可以工作，但有一點小錯誤。您不應使用list獲取JSONArray jsonList。

此作品（測試）：

// this string is just used for testing, use your response... 
String json = "[[\"Fitch's Chemist\",\"731 Hay St\",\"(08) 9321 6411\"]," 
      + "[\"Ferrara Karaoke Bar\",\"67 Milligan Street\",\"(08) 9481 1909\"]," 
      + "[\"Target: Perth\",\"712-720 Hay St\",\"(08) 9327 3700\"]," 
      + "[\"C Restaurant\",\"44 St Georges Tce\",\"(08) 9220 8333\"]," 
      + "[\"Celona Joe Tailors\",\"146 Murray St\",\"(08) 9325 8274\"]," 
      + "[\"Fashion In Colour\",\"Shop 2, 138 Barrack St\",\"(08) 9218 8233\"]," 
      + "[\"Mainpeak\",\"858 Hay St\",\"(08) 9322 9044\"]," 
      + "[\"Fj Storen Painting Contractors\",\"34 Queen St\",\"(08) 9486 9292\"]," 
      + "[\"Financial Pathfinders\",\"Level 4/81 St Georges Tce\",\"(08) 9213 9699\"]," 
      + "[\"Seasons of Perth\",\"37 Pier St\",\"(08) 9325 7655\"]," 
      + "[\"David Jones\",\"622 Hay St\",\"(08) 9210 4000\"]," 
      + "[\"Pharmacity Chemist Supermart\",\"717 Hay St\",\"(08) 9322 6921\"]," 
      + "[\"Austcare\",\"10 Pier St\",\"(08) 9325 9330\"]," 
      + "[\"Western Australia\",\"8 Pier St\",\"(08) 9261 6222\"]," 
      + "[\"Oceanic Cruises\",\"5 Barrack\",\"(08) 9325 1191\"]]"; 

try { 
    JSONArray jsonArray = new JSONArray(json); 
    List<String> list = new ArrayList<String>(); 
    for (int i = 0; i < jsonArray.length(); i++) { 
     list.add(jsonArray.getString(i)); 
     // thats the correct line: 
     JSONArray jsonList = new JSONArray(jsonArray.getString(i)); 
     // Used for debug/test, use your own objects BusinessName, Address and TelNo 
     System.out.println(jsonList.getString(0) + ":" + jsonList.getString(1) + ":" + jsonList.getString(2)); 
    } 
} catch (JSONException e) { 
    // TODO Auto-generated catch block 
    e.printStackTrace(); 
} 

Answer 2

比方說，你有一個JSONArray變量稱爲jsonArray，它包含您的數據。

提取數據，你需要做什麼用：

jsonArray.getJSONObject（INT指數）（返回一個JSONObject） - 使用來獲取對象 jsonArray.getJSONArray（INT指數）內的對象（返回一個JSONArray） - 用於獲得數組中的數組

其餘的是自解釋的。

jsonArray.get（INT指數）（返回一個Object） jsonArray.getBoolean（INT指數）（返回一個布爾） jsonArray.getDouble（INT指數）（返回Double） jsonArray.getInt（INT指數） （返回一個整數） jsonArray.getLong（int index）（返回一個Long） jsonArray.getString（int index）（返回一個字符串）