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這是我擁有的PHP代碼。
需要Java等價於PHP代碼的3DES解密
function decrypt($s_input, $s_key, $s_iv) {
$s_decrypted = pack("H*" , $s_input); // Hex to binary
$s_decrypted = mcrypt_decrypt (MCRYPT_3DES, $s_key, $s_decrypted, MCRYPT_MODE_CBC, $s_iv); // 3des decryption
return $s_decrypted;
}
echo encrypt('c37551bb77f741d0bcdc16497b4f97b1','123456781234567812345678','12345678');
什麼它基本上是解密3DES加密字符串(先將其轉換十六進制字符串使用包功能二進制文件,然後進行實際的解密)。
這完美的工作在PHP-4並打印「Hello World」消息。但是,如果我運行等效的Java代碼(jdk 1.6),它會將垃圾輸出打印爲 - ¬ªmjV= 7xl_ * * * * *。
有人可以幫助解決這個問題嗎?爲什麼Java沒有正確解密十六進制字符串。
private static String decrypt(String inputStr, String keyStr, String ivStr) throws Exception {
IvParameterSpec iv = new IvParameterSpec(ivStr.getBytes());
SecretKeySpec key = new SecretKeySpec(keyStr.getBytes(), "DESede");
inputStr = hexToString(inputStr, 2);
Cipher cipher = Cipher.getInstance("DESede/CBC/NoPadding");
cipher.init(Cipher.DECRYPT_MODE, key, iv);
byte[] decrypted = cipher.doFinal(inputStr.getBytes());
return new String(decrypted);
}
private static String hexToString(String input, int groupLength) {
StringBuilder sb = new StringBuilder(input.length()/groupLength);
for (int i = 0; i < input.length() - groupLength + 1; i += groupLength) {
String hex = input.substring(i, i + groupLength);
sb.append((char) Integer.parseInt(hex, 16));
}
return sb.toString();
}
public static void main(String[] args) throws Exception {
String decryptSignature = decrypt("c37551bb77f741d0bcdc16497b4f97b1", "123456781234567812345678", "12345678");
System.out.println(decryptSignature);
}
謝謝。你給的代碼,解決了問題! – user1289117 2012-03-23 23:22:00