變量不是在PHP PDO

Question

工作這是我的PHP PDO代碼：

<?php 
$number = 1; 
function result($conn) { 
    $sql = 'SELECT name FROM customerdata'; 
    foreach ($conn->query($sql) as $row) { 
     print " ". $number ."  ". $row['name'] . " <br> "; // this is line 6 

    } 
} 
result($conn); 
?> 

這是錯誤，我越來越：

Notice: Undefined variable: number in C:\xampp\htdocs\website\a.php on line 6 

Answer 1

傳遞數字變量作爲函數的參數。數字變量不存在於該函數中。如上所述，要麼作爲參數傳遞，要麼聲明數字變量作爲函數中的全局變量。

Answer 2

$number 

是一個變量。你應該這樣做

function result($conn) { 
    insert line global $number; 
    $sql = 'SELECT name FROM customerdata'; 
    foreach ($conn->query($sql) as $row) { 
     print " ". $number ."  ". $row['name'] . " <br> "; // this is line 6 

    } 
} 

Answer 3

你需要傳遞的數量爲arugument的功能

function result($conn,$number) { 
    $sql = 'SELECT name FROM customerdata'; 
     foreach ($conn->query($sql) as $row) { 
      print " ". $number ."  ". $row['name'] . " <br> "; 

     } 

    } 

Answer 4

你可以在這裏使用兩個選擇要麼通過$號作爲參數，或者在全球

聲明它溶膠1：

<?php 
$number = 1; 
function result($conn,$number) { 
    $sql = 'SELECT name FROM customerdata'; 
    foreach ($conn->query($sql) as $row) { 
     print " ". $number ."  ". $row['name'] . " <br> "; // this is line 6 

    } 
} 
result($conn,$number); 
?> 

溶膠2：

<?php 
$number = 1; 
function result($conn) { 
    global $number; 
    $sql = 'SELECT name FROM customerdata'; 
    foreach ($conn->query($sql) as $row) { 
     print " ". $number ."  ". $row['name'] . " <br> "; // this is line 6 

    } 
} 
result($conn); 
?>