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您能否解釋爲什麼只有第三個「複製鏈接」僅在所有面板都關閉時才起作用?
我希望我的複製鏈接可以在面板中打開,並且面板也可以打開。display:inline;不適用於複製鏈接
這是我的PAGE: http://500milligrammes.com/facticemagazine/final/0/
該處是我的代碼:
<!DOCTYPE HTML>
<!--[if IE 8]><html lang="en" class="lt-ie9"> <![endif]-->
<!--[if gt IE 8]><!-->
<html lang="en">
<!--<![endif]-->
<head>
<meta charset="utf-8">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1, maximum-scale=1">
<script type="text/javascript" src="https://code.jquery.com/jquery-2.1.0.js"></script>
<style>
.panel1,
.panel2 {
display: none;
border: 1px solid #ccc;
background-color: #eee
}
.flip1,
.flip2 {
border: 1px solid #ccc;
background-color: #eee
}
#check,
#check2 {
visibility: hidden;
width: 12px;
height: 12px;
}
span#copy-callbacks,
span#copy-callbacks2 {
float: none;
cursor: pointer;
}
</style>
<script type="text/javascript">
$(document).ready(function() {
$("span#copy-callbacks").zclip({
path: "ZeroClipboard.swf",
copy: $('#callback-paragraph').text(),
beforeCopy: function() {
$('#copy-callbacks').css('background', 'none');
},
afterCopy: function() {
$('#copy-callbacks').css('background', 'none');
}
});
document.getElementById("copy-callbacks").onclick = function() {
document.getElementById("check").style.visibility = "visible";
}
});
$(document).ready(function() {
$('span#copy-callbacks').hover(
function() {
$(this).css({
"color": "#e0ccb4"
});
},
function() {
$(this).css({
"color": "#000"
});
}
);
$("span#copy-callbacks2").zclip({
path: "ZeroClipboard.swf",
copy: $('#callback-paragraph2').text(),
beforeCopy: function() {
$('#copy-callbacks2').css('background', 'none');
},
afterCopy: function() {
$('#copy-callbacks2').css('background', 'none');
}
});
document.getElementById("copy-callbacks2").onclick = function() {
document.getElementById("check2").style.visibility = "visible";
}
});
$(document).ready(function() {
$('span#copy-callbacks2').hover(
function() {
$(this).css({
"color": "#e0ccb4"
});
},
function() {
$(this).css({
"color": "#000"
});
}
);
$(".flip1").click(function() {
$(".panel1").slideToggle("fast");
});
$(".flip2").click(function() {
$(".panel2").slideToggle("fast");
});
});
</script>
</head>
<body>
<div class="flip1">Click to slide the first panel down or up</div>
<div class="panel1">
when this panel is open, any copy link works !!!
</div>
<div style="margin-top:150px;" class="flip2">Click to slide the second panel down or up</div>
<div class="panel2">
when a copy link is inside a panel, it doesn't work !!!
<br/>
<br/>
<span id="copy-callbacks">Copy link <img src="check.png" id="check" style="display: inline;"></span>
<span style="font-size:0px;" id="callback-paragraph">essaie sans alert</span>
</div>
<div style="margin-top:150px; ">
This one works perfectly when all panels are closed !!
<br/>
<span id="copy-callbacks2">Copy link <img src="check.png" id="check2" style="display: inline;"></span>
<span style="font-size:0px;" id="callback-paragraph2">essaie sans alert</span>
</div>
<script type="text/javascript" src="jquery.zclip.js"></script>
<script type="text/javascript" src="jquery.cbpFWSlider.min.js"></script>
</body>
</html>
感謝傢伙,你幫了我很多,有效的位置是問題。爲了解決這個問題,我在query.zclip.js上工作 - >我通過繼承和刪除關於top和left px的行來更改位置absolution:D –
是的,你也可以這樣做。有幾種方法,z-index是最簡單的。將來使用代碼檢查器來突出顯示元素並查看所在的位置。覆蓋其他元素的定位元素是一個常見問題... –
只是一個問題,如何在面板內複製鏈接,爲什麼我們看不到邊框:1px純紅色; ? –