這是我的解決方法，使列表可選和排序，並允許套索實現。這裏是fiddle。
<html>
<meta charset="utf-8" />
<title>jQuery UI Sortable with Selectable</title>
<link rel="stylesheet" href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" />
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
$(function() {
//
$('body').selectable({
filter: 'li'
//filter: '#album2 > li'
});
/*
Since the sortable seems unable to move more than one object at a
time, we'll do this:
The LIs should act only as wrappers for DIVs.
When sorting a LI, move all the DIVs that are children of selected
LIs to inside the sorting LI (this will make them move together);
but before doing that, save inside the DIVs a reference to their
respective original parents, so we can restore them later.
When the user drop the sorting, restore the DIVs to their original
parent LIs and place those LIs right after the just-dropped LI.
Voilá!
Tip: doesn't work so great if you try to stick the LIs inside the LI
*/
$('.connectedSortable').sortable({
connectWith: ".connectedSortable",
delay: 100,
start: function(e, ui) {
var topleft = 0;
// if the current sorting LI is not selected, select
$(ui.item).addClass('ui-selected');
$('.ui-selected div').each(function() {
// save reference to original parent
var originalParent = $(this).parent()[0];
$(this).data('origin', originalParent);
// position each DIV in cascade
$(this).css('position', 'absolute');
$(this).css('top', topleft);
$(this).css('left', topleft);
topleft += 20;
}).appendTo(ui.item); // glue them all inside current sorting LI
},
stop: function(e, ui) {
$(ui.item).children().each(function() {
// restore all the DIVs in the sorting LI to their original parents
var originalParent = $(this).data('origin');
$(this).appendTo(originalParent);
// remove the cascade positioning
$(this).css('position', '');
$(this).css('top', '');
$(this).css('left', '');
});
// put the selected LIs after the just-dropped sorting LI
$('#album .ui-selected').insertAfter(ui.item);
// put the selected LIs after the just-dropped sorting LI
$('#album2 .ui-selected').insertAfter(ui.item);
}
});
//
});
<style>
*,
*:before,
*:after {
-webkit-box-sizing: border-box;
-moz-box-sizing: border-box;
box-sizing: border-box;
}
#album {
list-style: none;
float: left;
width: 20%;
border: 1px solid blue;
}
#album2 {
list-style: none;
float: left;
width: 20%;
border: 1px solid blue;
}
#album li {
float: left;
margin: 5px;
}
#album2 li {
float: left;
margin: 5px;
}
#album div {
width: 100px;
height: 100px;
border: 1px solid #CCC;
background: #F6F6F6;
}
#album2 div {
width: 100px;
height: 100px;
border: 1px solid #CCC;
background: #F6F6F6;
}
#album .ui-sortable-placeholder {
border: 1px dashed #CCC;
width: 100px;
height: 100px;
background: none;
visibility: visible !important;
}
#album2 .ui-sortable-placeholder {
border: 1px dashed #CCC;
width: 100px;
height: 100px;
background: none;
visibility: visible !important;
}
#album .ui-selecting div,
#album .ui-selected div {
background-color: #3C6;
}
#album2 .ui-selecting div,
#album2 .ui-selected div {
background-color: #3C6;
}
#anotheralbum {
list-style: none;
float: left;
width: 20%;
height: 800px;
border: 1px solid green;
}
</style>
<body>
<ul id="album" class="connectedSortable">
<li id="li1"><div>1- First</div></li>
<li id="li2"><div>2- Second</div></li>
<li id="li3"><div>3- Third</div></li>
<li id="li4"><div>4- Fourth</div></li>
<li id="li5"><div>5- Fifth</div></li>
<li id="li6"><div>6- Sixth</div></li>
<li id="li7"><div>7- Seventh</div></li>
<li id="li8"><div>8- Eighth</div></li>
</ul>
<ul id="album2" class="connectedSortable">
<li id="li1"><div>1- 1</div></li>
<li id="li2"><div>2- 2</div></li>
<li id="li3"><div>3- 3</div></li>
<li id="li4"><div>4- 4</div></li>
<li id="li5"><div>5- 5</div></li>
<li id="li6"><div>6- 6</div></li>
<li id="li7"><div>7- 7</div></li>
<li id="li8"><div>8- 8</div></li>
</ul>
<div id="anotheralbum" class="connectedSortable">
another album - no style for the lists inside here
</div>
<br style="clear:both">
</body>
</html>
剛剛使用鏈接答案中的代碼片段有什麼問題？用這段代碼，我很容易[得到這個工作]（http://jsfiddle.net/MattiasBuelens/vLM94/）。 –
當你放棄它時，只會拖動被拖動的物品而不是其他選擇的物品，我已經到了我正在實施它的階段。 –