解析和嵌套指針

我試圖寫一個程序，讀取包含四面體文件格式化爲這樣：解析和嵌套指針

T 109 20 10 19 
    [T X1 X2 X3 X4 ] 
    T 123 34 24 33 
    T 182 83 82 92

其中每行中的每個數字X表示三重峯（x的，y和z座標）在數據文件的行X：

line 1 x y z 
line 2 x y z 
    [.......] 
line n x y z

我在這裏Parsing data from ASCII formatted file in C發佈了類似（但簡單）的問題。這一次，我的想法是讀取四面體文件，並將表示這些四面體頂點座標的4行數字存儲在數組vertid[]（0到3）中，然後使用指向數組的指針數組將四面體鏈接到頂點Vertex結構。我將總結：將行ID號存儲在四面體結構中，然後在正確的頂點處將指針設置爲「點」。

請記住，我不是程序員（我需要這個來產生Voronoi圖）。如果不是存儲化妝四面體的頂點，而是存儲邊緣（因爲我相信實際上需要邊緣數據而不是用於生成Voronoi D的頂點數據）？我花了我的星期日在這工作，它不工作，我沒有理解爲什麼。謝謝。

（不工作）例如：

#define FILEPATHtri "/pathto/grid1DT.txt" 
#define FILEPATHorg "/pathto/grid1.txt" 
#define MAX 10000 

#include <assert.h> 
#include <stdio.h> 
#include <stdlib.h> 
#include "math.h" 



typedef struct 
{ 

    float x; 
    float y; 
    float z; 
    char ID; 
}Vertex; 

/* NOT USED ATM 
     typedef struct { 
      edge_ref next[4]; // pointers to other edges (AQE data structure) 
      void *data[4]; // pointers to endpoints of edge 
      unsigned ID; // ID of edge 
      }Edge; 
*/ 
typedef struct 
{ 
    Vertex *vert[4]; 
    int vertid[4]; 
    char t; 
}Tetra; 

void file_link (void) 
{ 

    Vertex *vert_dt = malloc(MAX * sizeof (Vertex)) ; 

    Vertex *vert_std = malloc(MAX * sizeof (Vertex)) ; 

    Tetra *tetrahedron = malloc(MAX * sizeof (Tetra)); 

    FILE *fp1,*fp2 ; 
    fp1 = fopen(FILEPATHtri,"r"); 
    int i = 0; 
    while(fscanf(fp1, "%c %i %i %i %i ", &tetrahedron[i].t, &tetrahedron[i].vertid[0], &tetrahedron[i].vertid[1], 
      &tetrahedron[i].vertid[2], &tetrahedron[i].vertid[3]) == 5) // Saving the line numbers into vertid[0..3] 
    { 
     i++; 
    } 
    fclose(fp1); 


    fp2 = fopen(FILEPATHorg,"r"); 
    int j = 0; 
    while(fscanf(fp2, "%f %f %f ", &vert_std[j].x, &vert_std[j].y, &vert_std[j].z) == 3) 
    { 
     j++; 
    } 
    fclose(fp2); 

    int n; 

    for (n=0; n<i; n++) { 

     tetrahedron[n]->vert[0]=vert_std[ tetrahedron[n].vertid[0] ]; // retriving coords from the standard file and storing 
     tetrahedron[n]->vert[1]=vert_std[ tetrahedron[n].vertid[1] ]; // them in the vertex pointer array of tretrahedron 
     tetrahedron[n]->vert[2]=vert_std[ tetrahedron[n].vertid[2] ]; 
     tetrahedron[n]->vert[3]=vert_std[ tetrahedron[n].vertid[3] ]; 
    } 
     int m = 100; //used to retrieve m'th tetra, so that I can print the tetra that I want,just for checking purposes.. 

     // printing 13 variables in total... 
     printf("These are the 4 coordinates of the vertices of the %i th tetrahedron from the DT file %f %f %f\n%f %f %f\n%f %f %f\n%f %f %f\n", n, 
       tetrahedron[n]->vert[0]->x,tetrahedron[n]->vert[0]->y,tetrahedron[n]->vert[0]->z, 
       tetrahedron[n]->vert[1]->x,tetrahedron[n]->vert[1]->y,tetrahedron[n]->vert[1]->z, 
       tetrahedron[n]->vert[2]->x,tetrahedron[n]->vert[2]->y,tetrahedron[n]->vert[2]->z, 
       tetrahedron[n]->vert[3]->x,tetrahedron[n]->vert[3]->y,tetrahedron[n]->vert[3]->z); 

    free(vert_dt); 
    free(vert_std); 
    free(tetrahedron); 
} 

int main(void) { 
    file_link(); 

    return 0; 
}

來源

2013-02-10 user1873500

格式類似於.OBJ格式，這是不太硬解析。你有它很好，你的錯誤在這一點上大多隻是拼寫錯誤。

就地只需使用數據，而不是指針：

Vertex *vert[4];

變爲：

Vertex vert[4];

您還需要更改所有的 ' - >' 符號，以點（。）符號，如：

tetrahedron[n].vert[0]=vert_std[ tetrahedron[n].vertid[0] ]; // retriving coords from the standard file and storing 
    tetrahedron[n].vert[1]=vert_std[ tetrahedron[n].vertid[1] ]; // them in the vertex pointer array of tretrahedron 
    tetrahedron[n].vert[2]=vert_std[ tetrahedron[n].vertid[2] ]; 
    tetrahedron[n].vert[3]=vert_std[ tetrahedron[n].vertid[3] ];

和你的測試代碼應該讓N回下來一個（這是目前lastLine所+ 1）：

// printing 13 variables in total... 
n--; // n must be last entry

最後，我得到一個編譯錯誤，你的分配，而不得不鍵入丟掉。

Vertex *vert_dt = (Vertex*) malloc(MAX * sizeof (Vertex)) ; 

Vertex *vert_std = (Vertex*) malloc(MAX * sizeof (Vertex)) ; 

Tetra *tetrahedron = (Tetra*) malloc(MAX * sizeof (Tetra));

注意，fscanf（）函數是相當嚴格的，所以用，比如說輸入文件，多餘的領先的空間可能會混淆該計劃。我在製作文件上測試了這些更改，因此不能保證。

希望這會有所幫助！這是我的完整文件：

#define FILEPATHtri "grid1DT.txt" 
#define FILEPATHorg "grid1.txt" 
#define MAX 10000 

#include <assert.h> 
#include <stdio.h> 
#include <stdlib.h> 
#include "math.h" 



typedef struct 
{ 

    float x; 
    float y; 
    float z; 
    char ID; 
}Vertex; 

/* NOT USED ATM 
     typedef struct { 
      edge_ref next[4]; // pointers to other edges (AQE data structure) 
      void *data[4]; // pointers to endpoints of edge 
      unsigned ID; // ID of edge 
      }Edge; 
*/ 
typedef struct 
{ 
    Vertex vert[4]; 
    int vertid[4]; 
    char t; 
}Tetra; 

void file_link (void) 
{ 

    Vertex *vert_dt = (Vertex*) malloc(MAX * sizeof (Vertex)) ; 

    Vertex *vert_std = (Vertex*) malloc(MAX * sizeof (Vertex)) ; 

    Tetra *tetrahedron = (Tetra*) malloc(MAX * sizeof (Tetra)); 

    FILE *fp1,*fp2 ; 
    fp1 = fopen(FILEPATHtri,"r"); 
    int i = 0; 
    while(fscanf(fp1, "%c %i %i %i %i ", &tetrahedron[i].t, &tetrahedron[i].vertid[0], &tetrahedron[i].vertid[1], 
      &tetrahedron[i].vertid[2], &tetrahedron[i].vertid[3]) == 5) // Saving the line numbers into vertid[0..3] 
    { 
     i++; 
    } 
    fclose(fp1); 


    fp2 = fopen(FILEPATHorg,"r"); 
    int j = 0; 
    while(fscanf(fp2, "%f %f %f ", &vert_std[j].x, &vert_std[j].y, &vert_std[j].z) == 3) 
    { 
     j++; 
    } 
    fclose(fp2); 

    int n; 

    for (n=0; n<i; n++) { 

     tetrahedron[n].vert[0]=vert_std[ tetrahedron[n].vertid[0] ]; // retriving coords from the standard file and storing 
     tetrahedron[n].vert[1]=vert_std[ tetrahedron[n].vertid[1] ]; // them in the vertex pointer array of tretrahedron 
     tetrahedron[n].vert[2]=vert_std[ tetrahedron[n].vertid[2] ]; 
     tetrahedron[n].vert[3]=vert_std[ tetrahedron[n].vertid[3] ]; 
    } 
     int m = 100; //used to retrieve m'th tetra, so that I can print the tetra that I want,just for checking purposes.. 

     // printing 13 variables in total... 
     n--; // rewind to last tetrahedron 
     printf("These are the 4 coordinates of the vertices of the %i th tetrahedron from the DT file %f %f %f\n%f %f %f\n%f %f %f\n%f %f %f\n", n, 
       tetrahedron[n].vert[0].x,tetrahedron[n].vert[0].y,tetrahedron[n].vert[0].z, 
       tetrahedron[n].vert[1].x,tetrahedron[n].vert[1].y,tetrahedron[n].vert[1].z, 
       tetrahedron[n].vert[2].x,tetrahedron[n].vert[2].y,tetrahedron[n].vert[2].z, 
       tetrahedron[n].vert[3].x,tetrahedron[n].vert[3].y,tetrahedron[n].vert[3].z); 

    free(vert_dt); 
    free(vert_std); 
    free(tetrahedron); 
} 

int main(void) { 
    file_link(); 

    return 0; 
}

來源

2013-02-10 21:47:33

解析和嵌套指針

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