我看了一堆教程,但我似乎無法弄清楚如何使用Pygame來完成Python 3上的字體。這裏是我的代碼:Pygame 3字體不會工作
import pygame
import time
import font
pygame.init
white = (255,255,255)
black = (0,0,0)
red = (255,0,0)
display_width = 800
display_height = 600
gameDisplay = pygame.display.set_mode((display_width,display_height))
pygame.display.set_caption('Slither')
gameExit = False
lead_x = display_width/2
lead_y = display_height/2
lead_x_change = 0
lead_y_change = 0
clock = pygame.time.Clock()
block_size = 10
FPS = 30
font = pygame.font.SysFont(None, 25)
def message_to_screen(msg,color):
screen_text = font.render(msg, True, color)
gameDisplay.blit(screen_text, [display_width/2, display_height/2])
while not gameExit:
for event in pygame.event.get():
if event.type == pygame.QUIT:
gameExit = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
lead_x_change = -block_size
lead_y_change = 0
elif event.key == pygame.K_RIGHT:
lead_x_change = block_size
lead_y_change = 0
elif event.key == pygame.K_UP:
lead_y_change = -block_size
lead_x_change = 0
elif event.key == pygame.K_DOWN:
lead_y_change = block_size
lead_x_change = 0
if lead_x >= display_width or lead_x < 0 or lead_y >= display_height or lead_y < 0:
gameExit = True
lead_x += lead_x_change
lead_y += lead_y_change
gameDisplay.fill(white)
pygame.draw.rect(gameDisplay, black, [lead_x,lead_y,block_size,block_size])
pygame.display.update()
clock.tick(FPS)
message_to_screen("You Lose", True, red)
pygame.display.update()
time.sleep(2)
pygame.quit()
quit()
我一直在關注「新波士頓」教程,而他的工作就是在他這樣做的時候。我是一名初學者。 –
@Penguini_The_Penguin你在代碼中沒有做錯任何事情,只是你忘記在'pygame.init'之後放置圓括號。您可以在'SysFont'中傳遞* None *;它會加載默認字體。 –