7
給定一個JSON名單如下:你如何在jsonpath中轉義@符號?
{
"listRel:customFieldList": {
"platformCore:customField": [
{
"@internalId": "801",
"scriptId": "custentity_admin_contact_cweb",
"@xsi:type": "platformCore:BooleanCustomFieldRef",
"platformCore:value": "false"
},
{
"@internalId": "712",
"@scriptId": "custentity_bar_number",
"@xsi:type": "platformCore:StringCustomFieldRef",
"platformCore:value": "166493"
},
{
"@internalId": "798",
"@scriptId": "custentity_contact_type",
"@xsi:type": "platformCore:SelectCustomFieldRef",
"platformCore:value": {
"@internalId": "1",
"@typeId": "148",
"platformCore:name": "Attorney"
}
}
]
}
}
我如何可以選擇 「custentity_bar_number」 的價值? 166493?
這會讓你在那裏,但只有當你在JSON中刪除@scriptId前的@符號。
$..['platformCore:customField'][?(@['scriptId'] == 'custentity_bar_number')]
所以我需要的是逃避在JSON @符號,並作出這樣的工作方式:
$..['platformCore:customField'][?(@['@scriptId'] == 'custentity_bar_number')]
我使用http://jsonpath.com/,試圖使這項工作。
哇!做得好!我不知道你可以插入這樣的代碼,它不在半官方文檔中http://goessner.net/articles/JsonPath/index.html#e2 – redwards510