使用Alamofire將圖像上傳到服務器

Question

我一直在我的應用程序中使用Alamofire通過多部分表單上傳請求上傳圖像。這是工作得很好，直到我實現JWT身份驗證和用戶登錄系統到我的CakePHP 3 REST API以下this documentation.在此之前，它工作時，它是絕對好的。上傳將是成功的，可以填充到我的數據庫中，並且您將能夠在服務器上看到圖像文件（通過Filezilla）。這個圖片上傳系統在我成功實現了帶有JWT身份驗證的登錄系統並剛剛設法解決這個問題之後便破產了。但是，我遇到的問題是上載請求是成功的，但是隻有圖像文件名正在我的數據庫中填充，我無法在Filezilla的服務器上查看圖像文件，這非常奇怪。任何人都可以指出我的方向是正確的，還是有人有過這個問題？它在我的控制檯日誌中取得成功，所以它應該在理論上起作用。

這裏是我的銀行代碼：

import UIKit 
import Foundation 
import Alamofire 
import SwiftyJSON 

class UploadImageController: UIViewController, UIImagePickerControllerDelegate, UINavigationControllerDelegate { 

var selectedImage: UIImage? 

override func viewDidLoad() { 
    super.viewDidLoad() 
} 

@IBOutlet weak var myImageView: UIImageView! 


override func viewDidAppear(_ animated: Bool) { 

    if selectedImage == nil { 
     let imagePicker = UIImagePickerController() 
     imagePicker.delegate = self 
     imagePicker.sourceType = UIImagePickerControllerSourceType.photoLibrary 
     imagePicker.allowsEditing = false 


     self.present(imagePicker, animated: true) 
    } 
} 

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo: [String : Any]) { 
    guard let image = didFinishPickingMediaWithInfo[UIImagePickerControllerOriginalImage] as? UIImage else { return } 
    selectedImage = image 
    myImageView.image = image 
    self.dismiss(animated: true, completion: nil) 
} 

@IBAction func uploadButtonTapped(_ sender: UIButton) { 
    guard let image = myImageView.image else { return } 
    upload(image) 
} 

override func viewWillDisappear(_ animated: Bool) { 
    selectedImage = nil 
    myImageView.image = nil 
} 

func upload(_ image: UIImage) { 

    let parameters: [String: String] = [ 
     "artist_id": "1" 
    ] 

    let imageData = UIImageJPEGRepresentation(image, 1)! 


    Alamofire.upload(multipartFormData: { multipartFormData in 
     multipartFormData.append(imageData, withName: "upload", fileName: "upload.jpg", mimeType: "image/jpeg") 

     for (key, value) in parameters { 
      multipartFormData.append(value.data(using: String.Encoding.utf8)!, withName: key) 
     } 

    }, to: "http://178.62.107.243/api/posts", 
     method:.post, 
     headers: ["Authorization": "Bearer \(Request.shared.token!)", 
     "Accept": "application/json", 
     "Content-Type": "application/json"], 
     encodingCompletion: { encodingResult in 
     switch encodingResult { 
     case .success(let upload, _, _): 
      upload.responseJSON { response in 
       debugPrint(response) 
      } 
     case .failure(let encodingError): 
      print(encodingError) 
     } 
    }) 

} 

} 

這是我的PHP代碼：

<?php 
namespace App\Controller\Api; 
use App\Controller\Api\AppController; 
use Cake\Log\Log; 

class PostsController extends AppController 
{ 
public $paginate = [ 
    'page' => 1, 
    'limit' => 500, 
    'maxLimit' => 500, 
    'contain' => ['Artists'] 
]; 


public function add() { 

    $this->Crud->on('beforeSave', function(\Cake\Event\Event $event) { 

     if(!empty($this->request->data['upload']['name'])) { 

      $file = $this->request->data['upload']; 
      $ext = substr(strtolower(strrchr($file['name'], '.')), 1); //get the extension 

      $arr_ext = ['jpg', 'png']; //set allowed extensions 

      $newFileName = time() . "_" . rand(000000, 999999); 

      //only process if the extension is valid 
      if (in_array($ext, $arr_ext)) { 
       //do the actual uploading of the file. First arg is the tmp name, second arg is 
       //where we are putting it 
       move_uploaded_file($file['tmp_name'], WWW_ROOT . 'img/posts/' . $newFileName . '.' . $ext); 

       //prepare the filename for database entry 
       $imageFileName = $newFileName; 

       $event->subject->entity->file_name = $imageFileName; 

      } 


     } 

    }); 

    $this->Crud->execute(); 

} 

} 

這裏是我在過去的20分鐘之做（如果這甚至可以幫助上傳請求）：

Database_posts table

Answer 1

當我處理多形式，我喜歡檢查鍵/值，以便我可以以不同的方式處理圖像。我不知道這是不是你的問題。這裏是我通常如何對待它：

// append parameters to request 
for (key, value) in object { 
    if value != nil{ 
     //image data 
     if value!.isKind(of: UIImage.self){ 
      // convert image to data and append to request 
      if let imageData = UIImageJPEGRepresentation(value as! UIImage, 1) { 
       multipartFormData.append(imageData, withName: key, fileName: "image.png", mimeType: "image/png") 
      } 
     } 
     //non-image data 
     else{ 
      let stringValue = String(describing: value!) 
      if let formData = stringValue.data(using: String.Encoding.utf8, allowLossyConversion: false){ 
       multipartFormData.append(formData, withName: key) 
      } 
     } 
    } 
    else{ 
     //no data for key (nil), don't send property 
    } 
}