Rails的友好ID定義路由

Question

我試圖讓我的路線是這樣工作的：

/articles/<category slug>/<article slug> 

我使用：

ruby '2.1.2' 
gem 'rails', '4.1.4' 
gem "friendly_id", "~> 5.0.1" 

我有了很多文章

類別

現在的url結構是：

/categories/

/用品/

，因爲我的routes.rb文件看起來像這樣：

resources :categories 
resources :articles 

我article.rb文件：

class Article < ActiveRecord::Base 
    belongs_to :category 

    extend FriendlyId 
    friendly_id :slug_candidates, use: [:slugged, :globalize] 

    def slug_candidates 
     [ 
     :name 
     ] 
    end 
end 

這裏是我的類別。 rb：

class Category < ActiveRecord::Base 
     has_many :articles 

     extend FriendlyId 
     friendly_id :slug_candidates, use: [:slugged, :globalize] 

     # Try building a slug based on the following fields in 
     # increasing order of specificity. 
     def slug_candidates 
      [ 
      :name 
      ] 
     end 
end 

如果我做這樣一個嵌套的路線：

resources :categories do 
    resources :articles 
end 

則結構變得/categories/<category slug>/articles/<article slug>

Answer 1

這正是我想要的。它擴展了mbillard的答案：

get "/articles", to: "articles#index" 
    resources :categories, path: 'articles' do 
    resources :articles, path: '', only: [:show] 
    end 
    resources :articles, only: [:index, :new, :edit, :create, :update, :destroy] 

Answer 2

你可以這樣做：

resources :categories do 
    get ':article_slug', to: 'articles#show' # => /categories/:category_id/:article_slug 
end 

甚至：

resources :categories do 
    resources :articles, path: '' 
end 

但要小心，因爲這會在/categories/:category_slug/.../之後收到任何東西。不過，我不知道像new和edit這樣的常規路線有什麼問題。