2014-03-13 60 views
1

我有一個表單更新單個表格行中的多個字段。其中一個字段需要是選擇/選項框,第一個選項是現有條目。從現有表條目的第一個選項中選擇選項

我已經試過這樣: -

while ($row=mysql_fetch_object($sql)) { 
$repairRqd = "'.$row->repair_required.'"; 
//print out table contents and add id into an array and email into an array 
echo '<tr> 
<td class="hidden"><input name="id3[]" value='.$row->id.' type="hidden" readonly> </td> 
<td align="center">'.$row->id.'</td> 
<td align="center">'.$row->repaired_by.'</td> 
<td align="center">'.date("l",strtotime($row->received_date)).'</br>'.$row->received_date.'</td> 
<td align="center"><input name="customer_name[]" value="'.$row->customer_name.'" maxlength = "50" size = "10"</td> 
<td align="center"><input name="repair_required[]" value="'.$row->repair_required.'" maxlength="249" size="40"></td> 
<td align="centre"><select name="status"> 
<option value="'.$row->status.'">'.$row->status.'</option> 
<option value="Received">Received</option> 
<option value="In Progress">In Progress</option> 
<option value="On Hold">On Hold</option> 
<option value="Written Off">Written Off</option> 
<option value="Cancelled">Cancelled</option> 
<option value="Complete">Complete</option> 
<option value="Dispatched">Dispatched</option> 
<option value="Collected">Collected</option> 
</select></td> 
</tr>'; 

隨着PHP: -

//get data from form 
$id3 = $_POST['id3']; 
$repairRequired = $_POST['repair_required']; 
$status1 = $_POST['status']; 
$customerName = $_POST['customer_name']; 

// set queries for each item in the row 
foreach ($id3 as $key => $value){ 
$query = "UPDATE repair SET repair_required = '$repairRequired[$key]' WHERE id = $value"; 
$query2 = "UPDATE repair SET status = '$status1[$key]' WHERE id = $value"; 
$query7 = "UPDATE repair SET customer_name = '$customerName[$key]' WHERE id = $value"; 
//execute query 
mysql_query($query); 
mysql_query($query2); 
mysql_query($query7); 
} 

奇怪的是,我得到的現有內容的選項列表中顯示出來,但是如果我改變它(通過選擇另一個選項)寫入數據庫的所有內容都是所選選項的第一個字母。

我在POST ['status']和變量$ status1上都做了一個var_dump,並且它們都顯示了我所期望的選擇的完整文本。

我不明白爲什麼完整的字符串沒有被寫入數據庫,並會非常感謝任何幫助嗎?

回答

0

改變的選擇的名稱作爲數組

<select name="status[]"> 

更新的代碼:

while ($row=mysql_fetch_object($sql)) { 
$repairRqd = "'.$row->repair_required.'"; 
//print out table contents and add id into an array and email into an array 
echo '<tr> 
<td class="hidden"><input name="id3[]" value='.$row->id.' type="hidden" readonly> </td> 
<td align="center">'.$row->id.'</td> 
<td align="center">'.$row->repaired_by.'</td> 
<td align="center">'.date("l",strtotime($row->received_date)).'</br>'.$row->received_date.'</td> 
<td align="center"><input name="customer_name[]" value="'.$row->customer_name.'" maxlength = "50" size = "10"</td> 
<td align="center"><input name="repair_required[]" value="'.$row->repair_required.'" maxlength="249" size="40"></td> 
<td align="centre"><select name="status[]"> 
<option value="'.$row->status.'">'.$row->status.'</option> 
<option value="Received">Received</option> 
<option value="In Progress">In Progress</option> 
<option value="On Hold">On Hold</option> 
<option value="Written Off">Written Off</option> 
<option value="Cancelled">Cancelled</option> 
<option value="Complete">Complete</option> 
<option value="Dispatched">Dispatched</option> 
<option value="Collected">Collected</option> 
</select></td> 
</tr>'; 
+0

謝謝。我無法看到它爲我的生活,但它現在很明顯:) – Jason

+0

我試圖但由於某種原因無法達到五分鐘。一旦我被系統允許,將盡快這樣做。 - 現在完成:) – Jason

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