波迪奧數量

Question

我利用上about.com斯蒂芬·查普曼的碼字的題爲「如何數字轉換爲詞用JavaScript。」問題是，我無法弄清楚跑道計算字段爲什麼不接受它。我不斷收到「腳本語法錯誤：非法返回聲明」。我做了一小段代碼並進行了測試，如果結束return和alert，它會顯示我想要的內容。在這方面沒有跑道接受什麼，有什麼選擇可以做到這一點。

語境：我使用這個自動生成合同，我很想有話可用。謝謝！

var th = ['', 'thousand', 'million', 'billion', 'trillion']; 
 
var dg = ['zero', 'one', 'two', 'three', 'four', 
 
    'five', 'six', 'seven', 'eight', 'nine' 
 
]; 
 
var tn = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 
 
    'seventeen', 'eighteen', 'nineteen' 
 
]; 
 
var tw = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']; 
 
var words = toWords(@PODIONUMBERFIELD); 
 

 
function toWords(s) { 
 
    s = s.toString(); 
 
    s = s.replace(/[\, ]/g, ''); 
 
    if (s != parseFloat(s)) return 'not a number'; 
 
    var x = s.indexOf('.'); 
 
    if (x == -1) x = s.length; 
 
    if (x > 15) return 'too big'; 
 
    var n = s.split(''); 
 
    var str = ''; 
 
    var sk = 0; 
 
    for (var i = 0; i < x; i++) { 
 
    if ((x - i) % 3 == 2) { 
 
     if (n[i] == '1') { 
 
     str += tn[Number(n[i + 1])] + ' '; 
 
     i++; 
 
     sk = 1; 
 
     } else if (n[i] != 0) { 
 
     str += tw[n[i] - 2] + ' '; 
 
     sk = 1; 
 
     } 
 
    } else if (n[i] != 0) { 
 
     str += 
 
     dg[n[i]] + ' '; 
 
     if ((x - i) % 3 == 0) str += 'hundred '; 
 
     sk = 1; 
 
    } 
 
    if ((x - i) % 3 == 1) { 
 
     if (sk) str += th[(x - i - 1)/3] + ' '; 
 
     sk = 0; 
 
    } 
 
    } 
 
    if (x != s.length) { 
 
    var y = s.length; 
 
    str += 
 
     'point '; 
 
    for (var i = x + 1; i < y; i++) str += dg[n[i]] + ' '; 
 
    } 
 
    return str.replace(/\s+/g, ' '); 
 
}

Answer 1

一切皆與你的腳本OK，你只需要重新安排它一下。 這裏是複製/粘貼的版本，對我來說真是棒極了：

var th = ['', 'thousand', 'million', 'billion', 'trillion']; 
var dg = ['zero', 'one', 'two', 'three', 'four', 
    'five', 'six', 'seven', 'eight', 'nine' 
]; 
var tn = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 
    'seventeen', 'eighteen', 'nineteen' 
]; 
var tw = ['twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']; 

function toWords(s) { 
    s = s.toString(); 
    s = s.replace(/[\, ]/g, ''); 
    if (s != parseFloat(s)) return 'not a number'; 
    var x = s.indexOf('.'); 
    if (x == -1) x = s.length; 
    if (x > 15) return 'too big'; 
    var n = s.split(''); 
    var str = ''; 
    var sk = 0; 
    for (var i = 0; i < x; i++) { 
    if ((x - i) % 3 == 2) { 
     if (n[i] == '1') { 
     str += tn[Number(n[i + 1])] + ' '; 
     i++; 
     sk = 1; 
     } else if (n[i] != 0) { 
     str += tw[n[i] - 2] + ' '; 
     sk = 1; 
     } 
    } else if (n[i] != 0) { 
     str += 
     dg[n[i]] + ' '; 
     if ((x - i) % 3 == 0) str += 'hundred '; 
     sk = 1; 
    } 
    if ((x - i) % 3 == 1) { 
     if (sk) str += th[(x - i - 1)/3] + ' '; 
     sk = 0; 
    } 
    } 
    if (x != s.length) { 
    var y = s.length; 
    str += 
     'point '; 
    for (var i = x + 1; i < y; i++) str += dg[n[i]] + ' '; 
    } 
    return str.replace(/\s+/g, ' '); 
} 


var words = toWords(@Number); 
words;