C中的連接字符串

Question

我的任務是將v1連接到v2，功能my_strcat()必須是void。我怎樣才能使用void函數來返回串聯的字符串？

int main(void){ 
    char v1[16], v2[16]; 
    int i1, i2; 
    printf("Enter First Name: \n"); 
    scanf("%s", v1); 
    printf("Enter Last Name: \n"); 
    scanf("%s", v2); 
    i1 = my_strlen(v1); 
    i2 = my_strlen(v2); 
    printf("len: %3d - string: %s \n", i1, v1); 
    printf("len: %3d - string: %s \n", i2, v2); 
    my_strcat(v1, v2); 
    printf("Concatenated String: %s \n", v1); 
    return 0; 
} 

void my_strcat (char s1[], char s2[]){ 
    int result[16]; 
    int i = 0; 
    int j = 0; 
    while(s1[i] != '\0'){ 
     ++i; 
     result[i]= s1[i]; 
    } 
    while(s2[j] != '\0'){ 
     ++j; 
     result[i+j] = s2[j]; 
    } 
    result[i+j] = '\0'; 
} 

Answer 1

void my_strcat (char s1[], char s2[],char result[]){ 
    int result[16]; 
    int i = 0; 
    int j = 0; 
    while(s1[i] != '\0'){ 
     result[i]= s1[i]; 
     ++i; 
    } 
    while(s2[j] != '\0'){ 
     result[i+j] = s2[j]; 
     ++j; 
    } 
    result[i+j] = '\0'; 
} 

你可以這樣做this..I的main（）宣佈第三結果字符串，其尺寸爲尺寸（V1）+尺寸（V2）+1

char result[33]; 
my_strcat(v1,v2,result); 

輸出：

Enter First Name: avinash 
Enter Last Name: pandey 
len: 7 - string: avinash 
len: 6 - string: pandey 
Concatenated String: avinashpandey