顯示期間出現Android AlertDialog錯誤

我正在開發一個android項目，在這一點上，我想要這種'fab'以onclick的方式，它帶有一個帶有文本輸入的彈出窗口。和兩個按鈕。但它帶來了我試圖修復的錯誤，最後我以爲我可以在這裏找到幫助。顯示期間出現Android AlertDialog錯誤

此行有一個錯誤：

AlertDialog.Builder builder = new AlertDialog.Builder(this); with this one too: final EditText input = new EditText(this);

private String m_Text = ""; 


@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main); 
    Toolbar toolbar = (Toolbar) findViewById(R.id.toolbar); 
    setSupportActionBar(toolbar); 

    FloatingActionButton fab = (FloatingActionButton) findViewById(R.id.fab); 
    fab.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 

      AlertDialog.Builder builder = new AlertDialog.Builder(this); 
      builder.setTitle("QuickSearch:"); 
      //input initial 
      final EditText input = new EditText(this); 
      // 
      input.setInputType(InputType.TYPE_CLASS_TEXT); 
      builder.setView(input); 
      // Set of buttons to be displayed. 
      builder.setPositiveButton("Go", new DialogInterface.OnClickListener() { 
       @Override 
       public void onClick(DialogInterface dialog, int which) { 
        m_Text = input.getText().toString(); 
       } 
      }); 
      builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { 
       @Override 
       public void onClick(DialogInterface dialog, int which) { 
        dialog.cancel(); 
       } 
      }); 

      builder.show(); 


      //Search action here. 
      //Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG) 
        // .setAction("Action", null).show(); 
     } 
    });

來源

2017-01-27 KE Keronei

你試過AlertDialog.Builder建設者=新AlertDialog.Builder（yourActivity.this）; –

上傳日誌？ –

您在每次點擊按鈕創建新實例Alertdialog ..無需拆卸視圖

試試這個：

AlertDialog.Builder builder = new AlertDialog.Builder(this); 
    final AlertDialog alert = builder.create(); 


    fab.setOnClickListener(new View.OnClickListener() { 
     @Override 
     public void onClick(View view) { 


      builder.setTitle("QuickSearch:"); 
      //input initial 
      final EditText input = new EditText(MainActivity.this); 
      // 
      input.setInputType(InputType.TYPE_CLASS_TEXT); 
      builder.setView(input); 
      // Set of buttons to be displayed. 
      builder.setPositiveButton("Go", new DialogInterface.OnClickListener() { 
       @Override 
       public void onClick(DialogInterface dialog, int which) { 
        m_Text = input.getText().toString(); 
       } 
      }); 
      builder.setNegativeButton("Cancel", new DialogInterface.OnClickListener() { 
       @Override 
       public void onClick(DialogInterface dialog, int which) { 
        alert.dismiss(); 
       } 
      }); 

      alert.show(); 


      //Search action here. 
      //Snackbar.make(view, "Replace with your own action", Snackbar.LENGTH_LONG) 
        // .setAction("Action", null).show(); 
     } 
    });

來源

2017-01-27 13:28:12 rafsanahmad007

@KE Keronei是否有效？ – rafsanahmad007

是的，謝謝。有效。 –

在您的代碼this指的是onClick不是context of that Activity。

代碼應該是這樣的

AlertDialog.Builder builder = new AlertDialog.Builder(YourActivityName.this); 
final EditText input = new EditText(YourActivityName.this);

What is the meaning of 「this」 in Java?

來源

2017-01-27 13:30:13 kId

顯示期間出現Android AlertDialog錯誤

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