傳遞XML資源的XMLReader

我想從我的res文件夾傳遞一個.xml文件到XMLReader以便將其解析到一個對象：傳遞XML資源的XMLReader

private void parseXML() { 
    String parsedData = ""; 
     try { 
      Log.w("AndroidParseXMLActivity", "Start"); 
      /** Handling XML */ 
      SAXParserFactory spf = SAXParserFactory.newInstance(); 
      SAXParser sp = spf.newSAXParser(); 
      XMLReader xr = sp.getXMLReader(); 

      QuestionXMLHandler myXMLHandler = new QuestionXMLHandler(); 
      xr.setContentHandler(myXMLHandler); 
      InputSource inStream = new InputSource(); 
      Log.w("AndroidParseXMLActivity", "Parse1"); 

      inStream.setCharacterStream(new StringReader(getResources().getXml(R.xml.questions).toString())); 
      Log.w("AndroidParseXMLActivity", "Parse2"); 

      xr.parse(inStream); 
      Log.w("AndroidParseXMLActivity", "Parse3"); 

      ArrayList<QuestionMaster> questionList = myXMLHandler.getQuestionsList(); 
      for(int i=0;i<questionList.size();i++){ 
       QuestionMaster question = questionList.get(i); 
       parsedData = parsedData + "----->\n"; 
       parsedData = parsedData + "Queston No: " + question.getQuestionNo() + "\n"; 
       parsedData = parsedData + "QuestionText: " + question.getQuestionText() + "\n"; 
       parsedData = parsedData + "CorrectAnswer: " + question.getQuestionText() + "\n"; 
       parsedData = parsedData + "WrongAnswer1: " + question.getQuestionText() + "\n"; 
       parsedData = parsedData + "WrongAnswer2: " + question.getQuestionText() + "\n"; 
       parsedData = parsedData + "WrongAnswer3: " + question.getQuestionText() + "\n"; 
       parsedData = parsedData + "Answered: " + question.isAnswered() + "\n"; 
       parsedData = parsedData + "QuestionText: " + question.isAnsweredCorrectly() + "\n"; 
      } 
      Log.w("AndroidParseXMLActivity", "Done"); 
     }catch (Exception e) { 
      Log.w("AndroidParseXMLActivity",e); 
     } 
     xmlOutput.setText(parsedData); 
    } 
}

我相信，這是該行：

inStream.setCharacterStream(new StringReader(getResources().getXml(R.xml.questions).toString()));

有人能指導我這個.xml文件傳遞給XMLReader。

編輯：

將其改爲：

InputSource inStream = new InputSource(getResources().openRawResource(R.raw.questions));

來源

2012-06-12 EHarpham

InputStream inStream = getResources().openRawResource(R.raw.questions); 
xr.parse(inStream);

來源

2012-06-12 11:58:59

感謝但是當我使用你的修改時，我得到的幫助：XMLReader類型中的方法解析（InputSource）不適用於參數（InputStream） – EHarpham

getXml()返回XmlPullParser的實現，所以它已經被設置爲parsed using that engine。將現有代碼更改爲使用XmlPullParser而不是SAX。

來源

2012-06-12 11:58:16 CommonsWare

我覺得你應該把文件無論是在原材料或資源文件夾使用SAX解析器，然後使用上下文讀取從那裏

Android版文件 - 閱讀從資產文件 http://www.javacodegeeks.com/2012/02/android-read-file-from-assets.html

來源

2012-06-12 12:01:51

傳遞XML資源的XMLReader

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