循環通過所有控件[MaterialSkin]（C＃）

Question

我想提出一個通用軟件，並在其中我加了一些標籤（我不能告訴更多... XD） 所以，我通過各種控制要循環在我的表或者至少所有的標籤...我已經試過

foreach (Control c in this.Controls) 
{ 
    //item.Font.Size = 11f; 
    c.ForeColor = Color.White; 
} 

但我認爲這只是循環到MaterialSkin.Controls.MaterialTabControl

，因爲當我嘗試用MaterialLabel..etc

foreach (MaterialLabel c in this.Controls) 
    { 
     //item.Font.Size = 11f; 
     c.ForeColor = Color.White; 
    } 

運行任意代碼

它告訴我

Additional information: Unable to cast object of type 'MaterialSkin.Controls.MaterialTabControl' to type 'MaterialSkin.Controls.MaterialLabel'. 

我需要幫助，請幫助我:) 我不是一個很優秀的程序員......所以，請幫助

現在要發揮造成4人死亡的xD

Answer 1

之前改變任何財產檢查，如果它是類型MaterialLabel。

foreach (Control c in this.Controls) 
{ 
    if(c.GetType()==typeof(MaterialLabel)) 
    { 
     c.Font = new Font(c.Font, FontStyle.Bold); 
     c.ForeColor = Color.White; 
    } 
} 

或LarsTech說：

foreach (MaterialLabel c in this.Controls.OfType<MaterialLabel>()) 
{ 
    c.Font = new Font(c.Font, FontStyle.Bold); 
    c.ForeColor = Color.White; 
} 

Answer 2

幾個選項...

foreach (var c in this.Controls) 
{ 
    if(c is MaterialLabel) 
    { 
     var i = (MaterialLabel)c; 
     i.Font = new Font(c.Font, FontStyle.Bold); 
     i.ForeColor = Color.White; 
    } 
} 

...

foreach (var c in this.Controls) 
{ 
    //slightly faster than the first version but won't work with struct 
    var i = c as MaterialLabel; 
    if(i != null) 
    { 
     i.Font = new Font(c.Font, FontStyle.Bold); 
     i.ForeColor = Color.White; 
    } 
} 

...

//cleanest 
foreach (var c in this.Controls.OfType<MaterialLabel>()) 
{ 
    c.Font = new Font(c.Font, FontStyle.Bold); 
    c.ForeColor = Color.White; 
}