如何判斷數組中的值是否在字符串中的次數

Question

想象一下，我有一個名爲uselessKeywords的數組。它具有「和」，「但」，「該」的值。

如果我還有一個帶有「cool，and，but，and」的字符串，我該如何判斷數組中的任何值在字符串中有多少次？

Answer 1

沿着這條線會做些什麼，但你必須注意假陽性，如andover和thesaurus。

$uselesskeywords = array('and', 'but', 'the'); 
$regex = implode('|', $uselesskeywords); 
$count = count(preg_grep("/($regex)/", "cool,and,but,and")); 

Answer 2

你可以遍歷在foreach uselessKeywords

馬克·B（中

$count = 0; 
foreach($uselessKeywords as $needle){ 
    $count = $count + substr_count($str, $needle); 
} 

echo $count; 

Answer 3

改進字符串添加一些昏迷消除誤報andover和thesaurus;我已經添加了前瞻，因爲有一些數值就逐一）：

$uselesskeywords = array('and', 'but', 'the'); 
$str = "cool,and,but,and"; 
$regex = implode('(?=,)|,', $uselesskeywords); 
$count = count(preg_grep("/,$regex(?=,)/", ",$str,")); 

Answer 4

試試這個..

<?php 
function uselessKeywordOccurances ($myString, $theArray) { 
    $occurances = array(); 
    $myTestWords = preg_split("/,/", $myString); 
    for($i = 0; $i < count($myTestWords); $i++)  { 
     $testWord = $myTestWords[$i]; 
     if (in_array($testWord, $theArray)) { 
      array_push($occurances, $testWord); 
     } 
    } 
    $grouped = array_count_values($occurances); 
    arsort($grouped); 
    return $grouped; 
} 

$uselessKeywords = array("and", "but", "the"); 
$testWords = "cool,and,but,and,and,the,but,wonderful"; 
$result = uselessKeywordOccurances($testWords, $uselessKeywords); 
var_dump($result); 
?> 

它應該返回uselessKeywords的出現，像這樣..

array(3) { ["and"]=> int(3) ["but"]=> int(2) ["the"]=> int(1) }