2011-05-05 40 views
1

我有一個允許用戶上傳圖像的頁面,該圖像由models.py文件存儲在{{MEDIA_ROOT}}/image/image1.jpg中 i要通過HTML圖像標記另一個網頁上顯示此圖像顯示用戶在django上傳的圖像

我的HTML代碼片段是<img border="2" src="{{ MEDIA_URL }}/images/{{ghar.image}}" alt="venture picture here"/>

這裏加爾的是,具有ABT圖像細節的對象

誰能幫我做相同

我使用的Django的框架和sqlite3的爲DB

更新

這是我的models.py功能

from django.db import models 

class GharData(models.Model): 
    place = models.CharField(max_length=40) 
    typeOfProperty = models.CharField(max_length=30) 
    typeOfPlace = models.CharField(max_length=20) 
    price = models.IntegerField() 
    ownerName = models.CharField(max_length=80) 
    ownerEmail = models.EmailField(blank=True, null=True) 
    address = models.CharField(max_length=200) 
    nameOfVenture = models.CharField(max_length=100) 
    city = models.CharField(max_length=60) 
    size = models.CharField(max_length=60) 
    designedBy = models.CharField(max_length=50,blank=True,null=True) 
    description = models.CharField(max_length=500,blank=True,null=True) 
    ownerPhone = models.CharField(max_length=20) 


    def __unicode__(self): 
     return self.ownerName 


class ImageData(models.Model): 
    property = models.ForeignKey(GharData, related_name='images') 
    image = models.ImageField(upload_to='image/',blank=True,null=True) 
    video = models.FileField(upload_to='video/',blank=True,null=True) 

    def __unicode__(self): 
     return self.property.ownerName 

這是urls.py

from django.conf.urls.defaults import patterns, include, url 
import settings 

# Uncomment the next two lines to enable the admin: 
from django.contrib import admin 
admin.autodiscover() 



urlpatterns = patterns('', 
    url(r'^$', 'gharnivas.views.index'), 
     url(r'^search/$', 'gharnivas.views.search'), 
    url(r'^venture/(?P<ghar_id>\d+)/$', 'gharnivas.views.venture'), 
    url(r'^media/(?P<path>.*)$','django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), 

    url(r'^admin/', include(admin.site.urls)), 
) 

非常感謝

回答

0

你可以箱子一個單獨的對象,它具有訪問的ImageData類GharData類的ID。

def Show_something(request, ghar_id): 
    g = get_object_or_404(GharData, pk=ghar_id) 
    i = g.images.all() 
    return render_to_response('YOUR_APP/iventure.html', {'ghar': g, 'imagedata' :i }, context_instance=RequestContext(request)) 

<img border="2" src="{{ MEDIA_URL }}{{ imagedata.image }}" alt="venture picture here"/> 
0

<img src="{{ [MODEL_OBJECT].[IMAGE_FIELD].url }}" />

你的情況:

<img border="2" src="{{ghar.image.url}}" alt="venture picture here" />

+0

@DrTyrsa:它沒有工作......我沒有得到的圖像 – 2011-05-05 08:52:20

+0

你在模型中使用'upload_to'?或者手動上傳某種方式?如果第二個 - src =「{{MEDIA_URL}}/{{ghar.image.name}}」'(或'src =「{{MEDIA_URL}}/images/{{ghar.image.name}}」') – DrTyrsa 2011-05-05 09:06:14

+0

@DrTr莎莎:我已經更新了這個問題。你能否檢查一下,請讓我知道我的錯誤? – 2011-05-05 09:10:41