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當我通過下面的方法執行一個API時,我總是得到404作爲響應代碼。HTTP POST方法返回狀態碼404
private void execute() throws IllegalStateException, IOException, NoSuchAlgorithmException {
Map<String, String> comment = new HashMap<String, String>();
comment.put("accounts-groups", "customers/enterprise");
comment.put("companyType", "customer");
comment.put("companyName", "Test");
String json = new GsonBuilder().create().toJson(comment, Map.class);
Log.i(TAG, "json : "+json);
HttpResponse response = makeRequest(URL, json);
/*Checking response */
if(response != null) {
InputStream inputStream = response.getEntity().getContent(); //Get the data in the entity
int statusCode = response.getStatusLine().getStatusCode();
Log.i(TAG, "statusCode : "+statusCode);
String result;
// convert inputstream to string
if(inputStream != null)
result = convertStreamToString(inputStream);
else
result = "Did not work!";
Log.i(TAG, "result : "+result);
}
}
private HttpResponse makeRequest(String uri, String json) throws NoSuchAlgorithmException {
Log.i(TAG, "uri : "+uri);
try {
HttpPost httpPost = new HttpPost(uri);
httpPost.setEntity(new StringEntity(json, HTTP.UTF_8));
long timestamp = System.currentTimeMillis();
String signatureKey = PRIVATE_KEY + timestamp;
byte[] bytesOfMessage = signatureKey.getBytes(HTTP.UTF_8);
MessageDigest md = MessageDigest.getInstance("MD5");
byte[] thedigest = md.digest(bytesOfMessage);
char[] signature = Hex.encodeHex(thedigest);
String finalSignature = String.valueOf(signature);
Log.i(TAG, "finalSignature : "+finalSignature);
httpPost.setHeader("Timestamp", ""+timestamp);
httpPost.setHeader("Api_token", API_TOKEN);
httpPost.setHeader("Signature" , finalSignature);
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader(HTTP.CONTENT_TYPE, "application/json");
return new DefaultHttpClient().execute(httpPost);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
我不明白我錯了什麼地方。任何人都可以幫助我嗎?
網址是正確的。他們在頂點代碼中使用的相同url並且工作正常。不知道java代碼中有什麼問題。 – Braj
我會在窗口上使用fiddler來調試這個請求,這將顯示服務器的確切內容,以及返回的內容 - 這也允許保存此類請求並在桌面上進行測試。 – marcinj
HTTPHost的第一個參數是我的系統IP地址,可以告訴我什麼是「params」n如何獲取它?我在ubuntu上 – Braj