var asdf:Array = [ [1,1] ];
trace(asdf.indexOf([1,1])); // -1
爲什麼indexOf()找不到[1,1]數組?AS3:多維數組中的indexOf()子陣
var asdf:Array = [ [1,1] ];
trace(asdf.indexOf([1,1])); // -1
爲什麼indexOf()找不到[1,1]數組?AS3:多維數組中的indexOf()子陣
這裏是一個小功能,我寫了,而以前,偉大工程。我包含了很多評論和一個示例搜索/函數來輸出結果。
// set up a multidimensional array that contains some data
var myArray:Array = new Array();
myArray.push(["granola","people... are great"," 4 ","10"]);
myArray.push(["bill","orangutan","buster","keaton"]);
myArray.push(["steve","gates","24","yes, sometimes"]);
myArray.push(["help","dave","jobs","hal"]);
// here we set up some properties on the array object to hold our search string and our results
myArray.myTarget = "steve";
myArray.myResults = [];
// now we call the search
myArray.forEach(multiSearch);
// this is the function that does all the heavy lifting....
function multiSearch(element:*, index:int, array:Array)
{
// see if we have a match in this array and pass back its index
for(var i:* in element)
{
if(element[i].indexOf(array.myTarget) > -1)
{
var tempArray:Array = array.myResults;
tempArray.push([index,i]);
array.myResults = tempArray;
}
}
}
// -------------------------------------------------------------------------------
// all the code below is OPTIONAL... it is just to show our results
// in the output window in Flash so you know it worked....
var printArray:Array = myArray.myResults;
for(var i:* in printArray)
{
trace("TARGET FOUND @: "+printArray[i][0]+", "+printArray[i][1]+" = "+myArray[ printArray[i][0] ][ printArray[i][1] ]);
}
// -------------------------------------------------------------------------------
這個工程。可能是因爲內部數組是鍵入的。
var qwer:Array = [1,1];
var asdf:Array = [qwer];
trace(asdf.indexOf(qwer)); // 0
不,它suceeds因爲QWER僅僅是一個數組引用 – Patrick 2010-07-14 19:57:49
它失敗,因爲當你做一個[x,y]
要創建一個新的數組,adsf
包含一個陣列和indexOf
尋找另外一個。
嘗試:
trace([1,1] == [1,1]);
你會看到,它打印錯誤,因爲數組作爲參考比較。
一個快速的indexOf功能,安排,以滿足您的需求:
function isElmEquals(e1:*, e2:*):Boolean {
return (e1==e2);
}
function isArrayEquals(a1:Array, a2:Array):Boolean {
if (a1==a2)
return true;
if ((a1==null) || (a2==null)) {
return false;
}
if (a1.length!=a2.length)
return false;
for (var i:int=0;i<a1.length;i++){
if (!isElmEquals(a1[i], a2[i]))
return false;
}
return true;
}
function indexOf(value:Array, into:Array):int{
var i:int = -1;
into.some(
function(item:*, index:int, array:Array):Boolean {
if (isArrayEquals(item as Array, value)) {
i = index;
return true;
}
return false;
}
);
return i;
}
var i:int=indexOf([1,1], [[-1,1], [0,1], [1,1], [1,-1]]);
trace(i);
var j:int=indexOf([1,2], [[-1,1], [0,1], [1,1], [1,-1]]);
trace(j);
這是裸機版本(你需要做它的工作,除了你的數組索引內容的唯一的東西): \t VAR myArray的:數組= new Array(); \t myArray.myTarget =「steve」; \t myArray.myResults = []; \t \t myArray.forEach(multiSearch); \t \t功能multiSearch(元素:*,索引:INT,數組:陣列) \t { \t \t爲(VAR I:*在元件) \t \t {\t \t \t \t如果(元素[I]。的indexOf(array.myTarget)> -1) \t \t \t { \t \t \t \t VAR tempArray:數組= array.myResults; \t \t \t \t tempArray.push([index,i]); \t \t \t \t array.myResults = tempArray; \t \t \t} \t \t} \t} – exoboy 2010-07-15 00:24:50
感謝。我剛剛添加了一個小小的新函數(asdf.find = function(){}),它受你的解決方案的啓發。 – embassyhill 2010-07-15 08:44:56
太棒了!總是能夠解釋人們需要的東西是很困難的...所以當解決方案有幫助時我總是很開心! – exoboy 2010-07-15 15:28:39