0
我的ProgressDialog不會顯示。在我的程序中，用戶從彈出菜單中選擇比特率，內容在線獲取並顯示在VideoView中。爲什麼ProgressDialog不能正確顯示？
但是，我得到的只是一個黑屏，視頻加載時，progressDialog會在視頻最終加載之前以秒爲單位顯示（或更少）。
private void showPopupMenu(View v){
popupMenu = new PopupMenu(VideoPlayer.this, v);
if(bitRates != null){
int menuItem = 0;
int index = bitRates.size()-1;
popupMenu.getMenu().add(0,menuItem, 0,"Hide menu");
for(int i=1;i<bitRates.size();i++){
menuItem = i;
popupMenu.getMenu().add(0,menuItem, 0,"Quality"+" : "+bitrateCheck(bitRates.get(index))).setCheckable(true);
Log.i("ITEM",qualityList.get(i)+" : "+bitRates.get(i));
index--;
}
popupMenu.getMenu().add(0,menuItem++, 0,"Catalog");
}
popupMenu.show();
popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
public boolean onMenuItemClick(final MenuItem item) {
p_dialog = ProgressDialog.show(VideoPlayer.this, "", "Loading...");
//get current position of video to seek to
final int position = mVideoView.getCurrentPosition();
new Thread() {
public void run() {
try{
runOnUiThread(new Runnable() {
public void run() {
if(item.getTitle().equals("Catalog")){
backButtonVideo(new View(VideoPlayer.this));
}
else if(item.getTitle().equals("Hide menu")){
popupMenu.dismiss();
mVideoView.start();
}
else{
play(streamUrls.get(item.getItemId()),position);
}
}
});
}
catch (Exception e) {
Log.e("tag", e.getMessage());
}
p_dialog.dismiss();
}
}.start();
return true;
}
});
}
public void play(String _videoUri, int position){
Log.i(TAG,"URI is : "+Uri.parse(_videoUri).toString());
//View view = new View()
MediaController mc = new MediaController(VideoPlayer.this);
mVideoView.setMediaController(mc);
mVideoView.setVideoURI(Uri.parse(_videoUri));
mVideoView.requestFocus();
mVideoView.seekTo(position);
mVideoView.start();
}
////////////////////////用新代碼編輯：根據建議/////////// ////////// 現在對話框根本不顯示。
mVideoView.setOnPreparedListener(new MediaPlayer.OnPreparedListener() {
public void onPrepared(MediaPlayer mp) {
// TODO Auto-generated method stub
mVideoView.start();
}
});
/////////////////////// ////////////////////
popupMenu.show();
popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() {
public boolean onMenuItemClick(final MenuItem item) {
//get current position of video to seek to
final int position = mVideoView.getCurrentPosition();
p_dialog = ProgressDialog.show(VideoPlayer.this, "", "Loading...");
try{
if(item.getTitle().equals("Catalog")){
backButtonVideo(new View(VideoPlayer.this));
}
else if(item.getTitle().equals("Hide menu")){
popupMenu.dismiss();
mVideoView.start();
}
else{
play(streamUrls.get(item.getItemId()),position);
}
}
catch (Exception e) {Log.e("tag", e.getMessage());}
return true;
}
});
}
public void play(String _videoUri, int position){
Log.i(TAG,"URI is : "+Uri.parse(_videoUri).toString());
MediaController mc = new MediaController(VideoPlayer.this);
mVideoView.setMediaController(mc);
mVideoView.setVideoURI(Uri.parse(_videoUri));
mVideoView.requestFocus();
mVideoView.seekTo(position);
p_dialog.dismiss();
}
我懷疑，如果你在做uithread的每一件事情......那你爲什麼要創建一個新線程，然後在那裏使用runonuithread？ – 5hssba 2012-04-12 15:32:05
@raju，沒有runOnUiThread我的play（）方法永遠不會被調用。 – Fabii 2012-04-12 15:33:36
@raju，Im刪除了新線程並保留了uithread，問題仍在發生。如果要擺脫uiThread我會遇到一個looper.prepare（）問題。 – Fabii 2012-04-12 15:44:08