在Ruby中執行XMLHttpRequest的最簡單方法是什麼？

Question

我想在Ruby中做一個XMLHttpRequest POST。我不想使用像Watir這樣的框架。像Mechanize或Scrubyt就好了。我怎樣才能做到這一點？

Answer 1

XMLHTTPRequest是一個瀏覽器的概念，但是因爲你問的是Ruby，我假設你想要做的就是從ruby腳本中模擬這樣的請求嗎？爲此，有一個名爲HTTParty的寶石，它非常易於使用。

這裏有一個簡單的例子（假設你有寶石 - 與gem install httparty安裝）：

require 'httparty' 
response = HTTParty.get('http://twitter.com/statuses/public_timeline.json') 
puts response.body, response.code, response.message, response.headers.inspect 

Answer 2

機械化：

require 'mechanize' 
agent = Mechanize.new 
agent.post 'http://www.example.com/', :foo => 'bar' 

Answer 3

例與 '網/ HTTP'，（紅寶石1.9.3 ）：

您只需將XMLHttpRequest的附加頭添加到您的POST請求中（請參閱下文）。

require 'net/http' 
require 'uri' # convenient for using parts of an URI 

uri = URI.parse('http://server.com/path/to/resource') 

# create a Net::HTTP object (the client with details of the server): 
http_client = Net::HTTP.new(uri.host, uri.port) 

# create a POST-object for the request: 
your_post = Net::HTTP::Post.new(uri.path) 

# the content (body) of your post-request: 
your_post.body = 'your content' 

# the headers for your post-request (you have to analyze before, 
# which headers are mandatory for your request); for example: 
your_post['Content-Type'] = 'put here the content-type' 
your_post['Content-Length'] = your_post.body.size.to_s 
# ... 
# for an XMLHttpRequest you need (for example?) such header: 
your_post['X-Requested-With'] = 'XMLHttpRequest' 

# send the request to the server: 
response = http_client.request(your_post) 

# the body of the response: 
puts response.body