junit和easymock，同時保存異常

Question

我正在使用EasyMock和JUnit。我在保存時遇到異常。請找到下面的代碼。 EasyMock.explay（someDao.save（pojo））。andReturn（pojo）; // pojo我創建了值 EasyMock.replay（someDao）;

Pojo savedObject = someService.save（pojo）;

但someService.save（pojo）在保存之前調用另一個服務。那麼如何嘲笑該服務？

謝謝， 大衛

Answer 1

用同樣的方法：

SomeDao someDao = createMock(SomeDao.class); 
SomeOtherDao someOtherDao = createMock(SomeOtherDao.class); 
someService.setSomeDao(someDao); 
someService.setSomeOtherDao(someOtherDao); 
EasyMock.expect(someOtherDao.save(pojo)).andReturn(pojo); 
EasyMock.expect(someDao.save(pojo)).andReturn(pojo); 
EasyMock.replay(someOtherDao, someDao); 

Pojo savedObject = someService.save(pojo);