如何突破父母功能？

Question

如果我想突破某個功能，我可以撥打return。

如果我在一個子函數中，並且想要跳出調用子函數的父函數，該怎麼辦？有沒有辦法做到這一點？

小例子：

def parent(): 
    print 'Parent does some work.' 
    print 'Parent delegates to child.' 
    child() 
    print 'This should not execute if the child fails(Exception).' 

def child(): 
    try: 
     print 'The child does some work but fails.' 
     raise Exception 
    except Exception: 
     print 'Can I call something here so the parent ceases work?' 
     return 
    print "This won't execute if there's an exception." 

Answer 1

這就是異常處理是：

def child(): 
    try: 
     print 'The child does some work but fails.' 
     raise Exception 
    except Exception: 
     print 'Can I call something here so the parent ceases work?' 
     raise Exception # This is called 'rethrowing' the exception 
    print "This won't execute if there's an exception." 

然後父功能不會趕上例外，它會繼續往上走棧，直到它找到某人。

如果你想重新拋出同樣的異常，你可以只使用raise：

def child(): 
    try: 
     print 'The child does some work but fails.' 
     raise Exception 
    except Exception: 
     print 'Can I call something here so the parent ceases work?' 
     raise # You don't have to specify the exception again 
    print "This won't execute if there's an exception." 

或者，您可以將Exception轉換成說像raise ASpecificException更具體的東西。