2012-08-22 57 views
3

我有這樣結果沒有連接條件

SELECT COUNT(u.user_id) AS count1 FROM users WHERE user_id>1001 
UNION 
SELECT COUNT(c.hits) AS count2 FROM source c WHERE loginid LIKE 'fb%'; 

結果查詢

count1 
250 
56 

如何可以把它在一個單行進行這樣

count1 count2 
250  56 

回答

3
select 
    (SELECT COUNT(u.user_id) AS count1 from users where user_id>1001) as count1, 
    (select count(c.hits) AS count2 from source c where loginid like 'fb%') as count2 
+0

非常感謝你。 – syncdm2012

1
SELECT SUM(count1) AS count1, 
     SUM(count2) AS count2 
FROM(
    SELECT COUNT(u.user_id) AS count1, 0 AS count2 from users where user_id>1001 

    UNION ALL 

    SELECT 0 AS count1, count(c.hits) AS count2 from source c where loginid like 'fb%'; 
)a; 
+0

這不會工作,因爲上面的查詢不會在內部查詢中找到count2列。 Dumitrescu Bogdan給出了正確的答案 – syncdm2012

+0

它將作爲'UNION'需要具有相同別名的相同數量的列。你爲什麼不嘗試呢?請參閱http://dev.mysql.com/doc/refman/5.6/en/union.html – Omesh