SQL異常：索引超出範圍

當我運行我的程序時，它顯示列超出範圍的錯誤。連接正常SQL異常：索引超出範圍

對於〔實施例

updateRecoredtoStudent(15, "Annies","Bot"," Ionia", "1/1/2013","firstname","Anny")

private static void updateRecordToStudent(int studentid, String firstname, String lastname,String address, String dateofbirth, String cond_col, String cond_val) throws SQLException { 

    Connection dbConnection = null; 
    PreparedStatement preparedStatement = null; 

    String updateTableSQL = "UPDATE student SET 'studentid' = ? 'firstname' = ? 'lastname' = ? 'address' = ? dateofbirth' = ? WHERE ? = ?"; 
    try { 
     dbConnection = getDBConnection(); 
     preparedStatement = dbConnection.prepareStatement(updateTableSQL); 

        preparedStatement.setInt(1, studentid); 
     preparedStatement.setString(2, firstname); 
        preparedStatement.setString(3, lastname); 
        preparedStatement.setString(4, address); 
        preparedStatement.setString(5, dateofbirth); 
        preparedStatement.setString(6, cond_col); 
        preparedStatement.setString(7, cond_val); 


     // execute update SQL stetement 
     preparedStatement.executeUpdate(); 

     System.out.println("Record is updated to STUDENT table!"); 

    } catch (SQLException e) { 

     System.out.println(e.getMessage()); 

    } finally { 

     if (preparedStatement != null) { 
      preparedStatement.close(); 
     } 

     if (dbConnection != null) { 
      dbConnection.close(); 
     } 

    } 

}

Student table contains 
-studentid(int-PK) 
-Firstname(String) 
-lastname(String) 
-Address(String) 
-Dateofbirth(String)

來源

2015-09-27 ʚïɞ Gemini ʚïɞ

你有拼寫錯誤（缺少引號）。您也有錯誤的索引（多次5） – cghislai

您不能將列名稱作爲準備語句中的參數 - http://stackoverflow.com/questions/20008336/having-a-column-name-as-input-parameter -'--------------------------- - 「 –

SET'studentid'=？'是無效的SQL。列名需要用雙引號括起來，而不是單引號（或者根本沒有引號） –

我認爲你錯了代碼語句。請嘗試以下。

String updateTableSQL = "UPDATE student SET 'studentid' = ? 'firstname' = ? 'lastname' = ? 'address' = ? dateofbirth' = ? WHERE " + cond_col + "= ?"; 
try { 
    dbConnection = getDBConnection(); 
    preparedStatement = dbConnection.prepareStatement(updateTableSQL); 

    preparedStatement.setInt(1, studentid); 
    preparedStatement.setString(2, firstname); 
    preparedStatement.setString(3, lastname); 
    preparedStatement.setString(4, address); 
    preparedStatement.setString(5, dateofbirth); 
    preparedStatement.setString(6, cond_val);

來源

2015-09-27 11:39:36 T8Z

我認爲但是所有的輸入都正確，表中有相應的限制 –

我認爲sql查詢中的錯誤，可能是在準備好的語句中 –

它作品。你呢 –

String updateTableSQL = "UPDATE student SET studentid = ?, firstname = ?, lastname = ?, address = ?, dateofbirth = ? WHERE "+cond_col+" = ?"; 
preparedStatement.setInt(1, studentid); 
preparedStatement.setString(2, firstname); 
preparedStatement.setString(3, lastname); 
preparedStatement.setString(4, address); 
preparedStatement.setString(5, dateofbirth); 
preparedStatement.setString(6, cond_val);

只有列值可以被設置。如果你想傳遞動態列名，你應該用查詢來連接它。列名之間缺少,還有一件事。

來源

2015-09-27 11:42:36 Satya

你還需要刪除列名周圍的''''。否則，你試圖給字符串賦值，這是行不通的。 –

@ tham @ Luke Woodward – Satya

好的，我會試試。謝謝你的幫助 –

更改您的SQL語法是這樣的：

UPDATE table_name 
SET column1=value1,column2=value2,... 
WHERE some_column=some_value;

所以你的SQL UPDATE查詢將是：

String updateTableSQL = "UPDATE student SET studentid=?, firstname=?, lastname=?, address=?, dateofbirth=? WHERE " + fieldName + " = ?";

來源

2015-09-27 11:47:20 roeygol

它的工作。謝謝你 –

好，你可以投票贊成有效的答案。 – roeygol

SQL異常：索引超出範圍

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