2017-01-30 149 views
-1

我寫了一個掃雷問題的代碼。它創建一個MxN掃雷遊戲,其中每個單元格都是概率爲p的炸彈。打印m-n遊戲和相鄰的炸彈計數。 Code:異常在線程「主」java.lang.ArrayIndexOutOfBoundsException:0錯誤

class Minesweeper { 
    public static void main(String[] args) { 
     int m = Integer.parseInt(args[0]); 
     int n = Integer.parseInt(args[1]); 
     double p = Double.parseDouble(args[2]); 

    try { 
     boolean[][] bombs = new boolean[m+2][n+2]; 
     for (int i = 1; i <= m; i++) 
      for (int j = 1; j <= n; j++) 
       bombs[i][j] = (Math.random() < p); 


     for (int i = 1; i <= m; i++) { 
      for (int j = 1; j <= n; j++) 
       if (bombs[i][j]) System.out.print("* "); 
       else    System.out.print(". "); 
      System.out.println(); 
     } 


     int[][] sol = new int[m+2][n+2]; 
     for (int i = 1; i <= m; i++) 
      for (int j = 1; j <= n; j++) 
       // (ii, jj) indexes neighboring cells 
       for (int ii = i - 1; ii <= i + 1; ii++) 
        for (int jj = j - 1; jj <= j + 1; jj++) 
         if (bombs[ii][jj]) sol[i][j]++; 


     System.out.println(); 
     for (int i = 1; i <= m; i++) { 
      for (int j = 1; j <= n; j++) { 
       if (bombs[i][j]) System.out.print("* "); 
       else    System.out.print(sol[i][j] + " "); 
      } 
      System.out.println(); 
     } 
    } 
    catch (Exception e) { 
     e.printStackTrace(); 
    } 

    } 
} 

我需要解析後,得到的情況?

int m = Integer.parseInt(args[0]); 
int n = Integer.parseInt(args[1]); 
double p = Double.parseDouble(args[2]); 

請幫幫我。

+3

的可能的複製[什麼原因導致java.lang.ArrayIndexOutOfBoundsException,如何預防呢?](http://stackoverflow.com/questions/5554734/what-c​​auses-a-java-lang-arrayindexoutofboundsexception -and-怎麼辦-I-防止-IT) – SomeJavaGuy

回答

1

在解析參數之前只需提供一個額外的條件。

if (args.length >= 3) { 
    m = Integer.parseInt(args[0]); 
    n = Integer.parseInt(args[1]); 
    p = Double.parseDouble(args[2]); 
} 
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