如何找到在Windows命令文本文件串並複製下一個5個字符

Question

我已經INPUT.TXT：

 
asdfasfasdfa,abc12345,abc98591,abc13456,abc95934,abc53455 
safasdfasdfa,abc31212,abc55455,abc23124,abc54834,abc13689 
... 

我需要output.txt中：

 
12345 
98591 
13456 
95934 
53455 
31212 
55455 
23124 
54834 
13689 

所以我需要找到所有「 abc「字符串並將下5個字符（在」abc「之後）複製到新文件中，每個數字必須換行。

Answer 1

檢查出來：

@echo OFF &SETLOCAL 
FOR %%f IN (*.txt) DO (
    ECHO Processing %%f --^> %%~nf.txt.new 
    (for /f "usebackq delims=" %%a in ("%%~f") do call:doit "%%a")>"%%~nf.txt.new" 
) 
GOTO :EOF 

:doit 
SET "line=%~1" 
SET "first=true" 
:loop 
SET "token=" 
FOR /f "tokens=1*delims=," %%b IN ("%line%") DO (
    SET "token=%%b" 
    SET "line=%%c" 
) 
SET "out=%token:~-5%" 
IF NOT DEFINED first ECHO(%out% 
SET "first=" 
IF DEFINED line GOTO :loop 
GOTO :EOF