我的Java經驗很少,我似乎無法找到任何解釋我如何解決我的問題;幾個小時我一直在嘗試不同的東西。在Java事件中訪問全局對象
我正在使用Phidgets RFID Java庫(http://www.phidgets.com/programming_resources.php)和JLayer,目的是根據傳感器範圍內的哪個RFID標籤播放不同的mp3文件。一旦RFID標籤不在範圍內,就需要停止播放。
的mp3音樂類:
// Import the JLayer classes
import javazoom.jl.player.*;
// Import the Java classes
import java.io.*;
public class mp3 {
private Player player;
private InputStream is;
/** Creates a new instance of MP3Player */
public mp3()
{
//
}
public void play(String filename)
{
try
{
// Create an InputStream to the file
is = new FileInputStream(filename);
}
catch(Exception e)
{
e.printStackTrace();
}
try
{
player = new Player(is);
PlayerThread pt = new PlayerThread();
pt.start();
}
catch(Exception e)
{
e.printStackTrace();
}
}
public void stop()
{
player.close();
}
class PlayerThread extends Thread
{
public void run()
{
try
{
player.play();
}
catch(Exception e)
{
e.printStackTrace();
}
}
}
}
和階級,一切事情發生:
import com.phidgets.*;
import com.phidgets.event.*;
public class ParrotDJ
{
public static final void main(String args[]) throws Exception {
RFIDPhidget rfid;
mp3 song = new mp3();
System.out.println(Phidget.getLibraryVersion());
rfid = new RFIDPhidget();
rfid.addAttachListener(new AttachListener() {
public void attached(AttachEvent ae)
{
try
{
((RFIDPhidget)ae.getSource()).setAntennaOn(true);
((RFIDPhidget)ae.getSource()).setLEDOn(true);
}
catch (PhidgetException ex) { }
System.out.println("attachment of " + ae);
}
});
rfid.addDetachListener(new DetachListener() {
public void detached(DetachEvent ae) {
System.out.println("detachment of " + ae);
}
});
rfid.addErrorListener(new ErrorListener() {
public void error(ErrorEvent ee) {
System.out.println("error event for " + ee);
}
});
rfid.addTagGainListener(new TagGainListener()
{
public void tagGained(TagGainEvent oe)
{
//System.out.println(oe);
if(oe.getValue().equals("0107ee6ed5") || oe.getValue().equals("0107ee75d5"))
{
System.out.println("Amanda Palmer - Leeds United");
song.play("leedsunited.mp3");
}else if(oe.getValue().equals("0107ee82c7") || oe.getValue().equals("0107ee89f0"))
{
System.out.println("Paolo Nutini - 10/10");
song.play("1010.mp3");
}else if(oe.getValue().equals("0107ee8644") || oe.getValue().equals("0107ee6ff2"))
{
System.out.println("Mozart - Eine Kleine Nachtmusik");
song.play("einekleinenachtmusik.mp3");
}
}
});
rfid.addTagLossListener(new TagLossListener()
{
public void tagLost(TagLossEvent oe)
{
//System.out.println(oe);
System.out.println("Stop");
song.stop();
}
});
rfid.addOutputChangeListener(new OutputChangeListener()
{
public void outputChanged(OutputChangeEvent oe)
{
System.out.println(oe);
}
});
rfid.openAny();
System.out.println("waiting for RFID attachment...");
rfid.waitForAttachment(1000);
System.out.println("Serial: " + rfid.getSerialNumber());
System.out.println("Outputs: " + rfid.getOutputCount());
System.out.println("Outputting events. Input to stop.");
System.in.read();
System.out.print("closing...");
rfid.close();
rfid = null;
System.out.println(" ok");
if (false) {
System.out.println("wait for finalization...");
System.gc();
}
}
}
我想有一個合理的解決方案,我只是努力讓我的頭圍繞事件驅動型的東西,以及Java的面向對象。我查了一下建設者模式,但是我現在無法掌握如何將這種情況應用於這種情況。
在此先感謝。
請問更具體的問題 – zacheusz