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我正在被加載的jQuery腳本,但是當我通過我正在此錯誤的PHP加載:當我看到未捕獲的類型錯誤:對象[對象的對象]無方法「facebookTrafficPop」
Uncaught TypeError: Object [object Object] has no method 'facebookTrafficPop'
通過Chrome瀏覽器開發consule,我可以看到它complaines哪些這一行:
jQuery().facebookTrafficPop({
這是我在我的PHP代碼:
<script type="text/javascript">
jQuery(document).ready(function(){
jQuery().facebookTrafficPop({
title: '<?php echo $params->get('title', 'Facebook Like Us Popup'); ?>',
message: '<?php echo $params->get('message', ''); ?>',
url: '<?php echo $params->get('url', $url); ?>',
showfaces: <?php echo $params->get('showfaces', '1'); ?>,
timeout: '<?php echo $params->get('timeout', '60'); ?>',
delay: '<?php echo $params->get('delay', '0'); ?>',
closeable: <?php echo $params->get('closeable', '1'); ?>,
advancedClose: <?php echo $params->get('advancedClose', '1'); ?>,
wait: '<?php echo $params->get('wait', '0'); ?>',
//lang: '<?php echo $params->get('lang', 'en'); ?>',
lang: '<?php echo $lang->getTag(); ?>',
opacity: '<?php echo $params->get('opacity', '25'); ?>'
});
});
</script>
,這就是我在Chrome中看到:
<script type="text/javascript">
//<script type="text/javascript" language="javascript">
// jQuery.noConflict();
jQuery(document).ready(function(){
jQuery().facebookTrafficPop({
**Uncaught TypeError: Object [object Object] has no method 'facebookTrafficPop'**
title: 'Facebook Like Us Popup',
message: '',
url: 'https://www.facebook.com/Arab.Dentist.Network',
showfaces: 1,
timeout: '60',
delay: '0',
closeable: 0,
advancedClose: 0,
wait: '0',
//lang: 'en',
lang: 'en-GB',
opacity: '25'
});
});
</script>
請讓我知道,如果你能解決這個問題有所幫助。
,如果我做什麼@Trew建議,我得到這個錯誤:Uncaught TypeError:Object function(a,b){return new e.fn.init(a,b,h)}沒有方法'facebookTrafficPop' – 2012-08-05 07:44:00
你有一些我們可以測試的網站,或者鏈接到哪裏獲取插件? – ThoKra 2012-08-05 07:45:04
當然,@Trew我現在在這裏加載它https://innovations-it.com/zoo_demo/en/social-web/facebook-like-us-popup-module – 2012-08-05 07:50:48