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我在使用INNER JOIN查詢時遇到問題。MYSQL加入條件可能爲空
我有兩個表。我需要部門名稱和所有三個批准者。如果任何審批者都是NULL,我也需要顯示。
mysql> desc department;
+-------------------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------+----------+------+-----+---------+----------------+
| id | int(8) | NO | PRI | NULL | auto_increment |
| departmentName | tinytext | YES | | NULL | |
| primaryApprover | int(8) | YES | | NULL | |
| secondaryApprover | int(8) | YES | | NULL | |
| tertiaryApprover | int(8) | YES | | NULL | |
+-------------------+----------+------+-----+---------+----------------+
mysql> desc approver;
+------------------+------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------------+------------+------+-----+---------+----------------+
| id | int(8) | NO | PRI | NULL | auto_increment |
| approverName | tinytext | YES | | NULL | |
| approverPosition | tinytext | YES | | NULL | |
| approverLogonId | tinytext | YES | | NULL | |
| approverEmail | tinytext | YES | | NULL | |
| isActive | tinyint(1) | YES | | NULL | |
+------------------+------------+------+-----+---------+----------------+
下面的查詢工作,但它並沒有給我數據,其中一次或二次審批是NULL:
SELECT
a.departmentName as DEPARTMENT,
pa.approvername as PRIMARY,
sa.approvername as SECONDARY,
ta.approvername as TERTIARY
FROM
department as a
INNER JOIN
approver pa on a.primaryapprover=pa.id
INNER JOIN
approver sa on a.secondaryapprover = sa.id
INNER JOIN
approver ta on a.tertiaryapprover = ta.id
ORDER BY
a.departmentname;
使用此查詢,我得到這樣的結果:
+--------------------------------+---------------------------+---------------------------+------------------------+
| DEPARTMENT | PRIMARY_APPROVER | SECONDARY_APPROVER | TERTIARY_APPROVER |
+--------------------------------+---------------------------+---------------------------+------------------------+
| Facilities | Washburn, Hoban | Cobb, Jayne | Reynolds, Malcomn |
| Personnel/HR | Frye, Kaylee | Serra, Inara | Book, Dariel |
+--------------------------------+---------------------------+---------------------------+------------------------+
2 rows in set (0.00 sec)
但應該得到這個結果:
+--------------------------------+---------------------------+---------------------------+------------------------+
| DEPARTMENT | PRIMARY_APPROVER | SECONDARY_APPROVER | TERTIARY_APPROVER |
+--------------------------------+---------------------------+---------------------------+------------------------+
| Business Office | NULL | Rample, Fanty | Niska, Adelei |
| Facilities | Washburn, Hoban | Cobb, Jayne | Reynolds, Malcomn |
| Personnel/HR | Frye, Kaylee | Serra, Inara | Book, Dariel |
| Technical Services | Tam, River | NULL | Tam, Simon |
+--------------------------------+---------------------------+---------------------------+------------------------+
4 rows in set (0.00 sec)
我不擅長連接......我在這裏錯過了什麼?
看起來你可以嘗試用'LEFT JOIN'替換所有'INNER JOIN'。這不會消除連接表中具有空值的行。 –