如何從文本中刪除具有特定類的所有DOM元素?從文本中刪除具有特定類的所有元素
var html = "<table>"+
"<tr>"+
"<td>1</td>"+
"<td>2</td>"+
"<td class='del'>3</td>"+
"</tr>"+
"<tr>"+
"<td>1</td>"+
"<td>2</td>"+
"<td class='del'>3</td>"+
"</tr>"+
"</table>";
如何從文本中刪除具有特定類的所有DOM元素?從文本中刪除具有特定類的所有元素
var html = "<table>"+
"<tr>"+
"<td>1</td>"+
"<td>2</td>"+
"<td class='del'>3</td>"+
"</tr>"+
"<tr>"+
"<td>1</td>"+
"<td>2</td>"+
"<td class='del'>3</td>"+
"</tr>"+
"</table>";
您可以HTML轉換成DOM對象,刪除指定的項目,並獲得它的HTML回:
var html = "<table>" +
"<tr>" +
"<td>1</td>" +
"<td>2</td>" +
"<td class='del'>3</td>" +
"</tr>" +
"<tr>" +
"<td>1</td>" +
"<td>2</td>" +
"<td class='del'>3</td>" +
"</tr>" +
"</table>";
var $obj = $(html); // Create jQuery object
$obj.find(".del").remove(); // Remove .del items
var htmlNew = $obj[0].outerHTML; // Get the updated HTML
// Demonstration purposes only:
$("body").text(htmlNew);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
請記住'.html()'只會返回內部html,在這種情況下將不包含'
['.remove()'](http://api.jque ry.com/remove/) – Andreas
你想從'html'變量中刪除它們,而不是從DOM中刪除它們? – Barmar