使用Jakarta HttpClient來模擬POST網絡請求

Question

我嘗試模仿由封閉的源應用程序發送的網絡請求。下面 是從關閉源應用程序所捕獲的網絡請求快照：

- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    Command: POST 
    - URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage? 
    Location: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    ProtocolVersion: HTTP/1.1 
    - ContentType: application/x-www-form-urlencoded 
    MediaType: application/x-www-form-urlencoded 
    Cache-Control: no-cache 
    Pragma: no-cache 
    UserAgent: Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06 
    Host: www.xxx.com:20000 
    Accept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2 
    Connection: keep-alive 
    ContentLength: 164 
    HeaderEnd: CRLF 
    - payload: HttpContentType = application/x-www-form-urlencoded 
    [SORT]: 0,1,0,10,5,0,KL,0 
    [FIELD]: 33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82 
    [LIST]: 1155.KL,1295.KL,7191.KL,0097.KL,2267.KL 

我使用的HttpClient模仿上述請求。

/** 
* @param args the command line arguments 
*/ 
public static void main(String[] args) { 
    try { 
     // TODO code application logic here 
     HttpClient httpClient = new HttpClient(); 
     httpClient.getParams().setParameter(HttpMethodParams.USER_AGENT, "Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06"); 

     PostMethod post = new PostMethod("http://www.xxx.com:20000/%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage?"); 

     NameValuePair[] data = { 
      new NameValuePair("SORT", "0,1,0,10,5,0,KL,0"), 
      new NameValuePair("FIELD", "33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82"), 
      new NameValuePair("LIST", "1155.KL,1295.KL,7191.KL,0097.KL,2267.KL") 
     }; 
     post.setRequestBody(data); 
     httpClient.executeMethod(post); 
     System.out.println(post.getResponseBodyAsString());  
    } 
    catch (Exception exp) { 
     exp.printStackTrace(); 
    } 
} 

但是，服務器端沒有迴應。我試圖捕捉我自己的網絡請求快照：

- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    Command: POST 
    - URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    Location: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    ProtocolVersion: HTTP/1.1 
    UserAgent: Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06 
    Host: www.xxx.com:20000 
    ContentLength: 234 
    - ContentType: application/x-www-form-urlencoded 
    MediaType: application/x-www-form-urlencoded 
    HeaderEnd: CRLF 
    - payload: HttpContentType = application/x-www-form-urlencoded 
    SORT: 0%2C1%2C0%2C10%2C5%2C0%2CKL%2C0 
    FIELD: 33%2C38%2C51%2C58%2C68%2C88%2C78%2C98%2C99%2C101%2C56%2C57%2C69%2C70%2C71%2C72%2C89%2C90%2C91%2C92%2C59%2C60%2C61%2C62%2C79%2C80%2C81%2C82 
    LIST: 1155.KL%2C1295.KL%2C7191.KL%2C0097.KL%2C2267.KL 

看來，有兩個主要不同：

（1）URI

（2）有效載荷

請問有什麼錯過了我的httpclient代碼？

經過多次實驗，我意識到，httpclient在我的有效載荷上執行URL編碼。它明確地轉向

1155.KL，1295.KL，7191.KL，0097.KL，2267.KL

到

1155.KL％2C1295.KL％2C7191.KL％2C0097.KL ％2C2267.KL

爲了避免這種情況，我編寫了一個測試代碼。以下測試代碼有效！

try { 
    Socket socket = new Socket("www.xxx.com", 20000); 
    PrintWriter out = new PrintWriter(socket.getOutputStream(), true); 
    final String body = "[SORT]=0,1,0,10,5,0,KL,0&[FIELD]=33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82&[LIST]=1155.KL,1295.KL,7191.KL,0097.KL,2267.KL"; 
    final int length = body.length(); 
    final String s = "POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage? HTTP/1.1\r\nContent-Type: application/x-www-form-urlencoded\r\nCache-Control: no-cache\r\nPragma: no-cache\r\nUser-Agent: Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06\r\nHost: www.xxx.com:20000\r\nAccept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2\r\nConnection: keep-alive\r\nContent-Length: "+length+"\r\n\r\n" + body; 
    out.println(s); 

    BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream())); 
    while(true) { 
      String ss = in.readLine(); 
      if (ss == null) break; 
      System.out.println(ss); 
    } 

} 
catch (Exception exp) { 
} 

以下是拍攝快照：

Frame: Number = 16, Captured Frame Length = 597, MediaType = ETHERNET 
+ Ethernet: Etype = Internet IP (IPv4),DestinationAddress:[7C-04-20-00-01-00],SourceAddress:[01-00-01-00-00-00] 
+ Ipv4: Src = 10.176.181.55, Dest = 202.75.55.23, Next Protocol = TCP, Packet ID = 956, Total IP Length = 583 
+ Tcp: Flags=...AP..., SrcPort=49253, DstPort=20000, PayloadLen=543, Seq=3920474750 - 3920475293, Ack=3537289604, Win=4380 (scale factor 0x2) = 17520 
- Http: Request, POST /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage 
    Command: POST 
    + URI: /%5bvUpJYKw4QvGRMBmhATUxRwv4JrU9aDnwNEuangVyy6OuHxi2YiY=%5dImage? 
    ProtocolVersion: HTTP/1.1 
    + ContentType: application/x-www-form-urlencoded 
    Cache-Control: no-cache 
    Pragma: no-cache 
    UserAgent: Mozilla/4.0 (Windows XP 5.1) Java/1.6.0_06 
    Host: n2ntbfd03.asiaebroker.com:20000 
    Accept: text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2 
    Connection: keep-alive 
    ContentLength: 164 
    HeaderEnd: CRLF 
    - payload: HttpContentType = application/x-www-form-urlencoded 
    [SORT]: 0,1,0,10,5,0,KL,0 
    [FIELD]: 33,38,51,58,68,88,78,98,99,101,56,57,69,70,71,72,89,90,91,92,59,60,61,62,79,80,81,82 
    [LIST]: 1155.KL,1295.KL,7191.KL,0097.KL,2267.KL 

Answer 1

由參數名稱顯示在您的捕獲SORT VS [分頁]的方式來看。我懷疑服務器期待您發送帶有多個表單控件數組，像

SORT = 0 & SORT = 1個& SORT = 0 ...

他們可能做到這一點作爲一種安全措施，因爲這樣可以不會用HTML來完成。

編輯：您需要將您的參數，這樣，

NameValuePair[] data = { 
     new NameValuePair("SORT", "0"), 
     new NameValuePair("SORT", "1"), 
     ... 
     new NameValuePair("FIELD", "33"), 
     ... 
    }; 

Answer 2

你是如何創建快照？參數名稱的括號是什麼意思？對於相同的參數，是否有多個值而不是逗號分隔的值，或者參數名稱是否應放在括號中？

Answer 3

您還缺少標題： 接受 的Cache-Control 附註

的單獨接受頭可能是足夠的服務器與一些有意義的迴應。嘗試這樣的事情對於HttpClient的4：

httpclient.addRequestInterceptor(new HttpRequestInterceptor() { 
     public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException { 
     request.setHeader("Pragma","no-cache"); 
     request.setHeader("Cache-Control","no-cache"); 
     request.setHeader("Accept","text/html, image/gif, image/jpeg, *; q=.2, */*; q=.2"); 
     } 
    }); 

或者這樣東西的HttpClient 3.x的：

method.setRequestHeader("Pragma","no-cache"); 
method.setRequestHeader("Cache-Control","no-cache"); 
method.setRequestHeader("Accept","text/html, image/gif, image/jpeg, *; q=.2, */*;