非法啓動類型錯誤

有人可以幫助我嗎？我有一個錯誤非法開始類型錯誤在行}）;我很困惑如何解決這個問題。任何幫助將不勝感激。該代碼如下所示：非法啓動類型錯誤

public SubokUlit(){ 
    String mgaPagkainTo[] = {"PM1 (Paa/ Spicy Paa with Thigh part)","PM2 (Pecho)","PM3 (Pork Barbeque 4 pcs.)","PM4 (Bangus Sisig)","PM5 (Pork Sisig)","PM6 (Bangus Inihaw)","SM1 (Paa)","SM2 (Pork Barbeque 2 pcs.)","Pancit Bihon","Dinuguan at Puto","Puto","Ensaladang Talong","Softdrinks","Iced Tea","Halo-Halo","Leche Flan","Turon Split"}; 
    JFrame frame = new JFrame("Mang Inasal Ordering System"); 
    JPanel panel = new JPanel(); 
    combo = new JComboBox(mgaPagkainTo); 
    combo.setBackground(Color.gray); 
    combo.setForeground(Color.red); 
    panel.add(combo); 
    frame.add(panel); 

    combo.addActionListener(new ActionListener(){ 
     public void actionPerformed(ActionEvent e){ 
      String str = (String)combo.getSelectedItem(); 
      a = str; 
      if(a == "PM1 (Paa/ Spicy Paa with Thigh part)"){ 
       Wew(); 
      } 
      else if(a == "PM2 (Pecho)"){ 
       Wew1(); 
      } 
     }); // I am getting an error in this line 
    } 

    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); 
    frame.setSize(300,100); 
    frame.setVisible(true); 
}

來源

2013-03-05 Angel Casi Montoya

你);是放錯了地方：它應該是}下一行後：

combo.addActionListener(new ActionListener(){ 
    public void actionPerformed(ActionEvent e){ 
     String str = (String)combo.getSelectedItem(); 
     a = str; 
     // Comparing strings should use equals, not == 
     if(a.equals("PM1 (Paa/ Spicy Paa with Thigh part)")){ 
      Wew(); 
     } else if(a.equals("PM2 (Pecho)")){ 
      Wew1(); 
     } 
    } // <<== Not here: this brace ends the method 
}); // <<== It should be after the brace that ends the anonymous class

來源

2013-03-05 10:42:47 dasblinkenlight

+1 - 我想下一個問題，我們將看到的是「爲什麼我的WEW/Wew1方法從來沒有所謂的」;） – 2013-03-05 10:49:23

@Andreas是你'對了，這是我的下一個問題。我應該爲我的下一個問題開始新的討論嗎？ – 2013-03-05 10:56:16

多數民衆贊成沒有必要 - 見http://stackoverflow.com/questions/767372/java-string-equals-versus – 2013-03-05 10:57:19

從

}); // I am getting an error in this line 
}

更改代碼

} // I am getting an error in this line 
}); 
^

來源

2013-03-05 10:43:28 Achrome

做到這一點

} // I am getting an error in this line 
});

，而不是這樣的：

}); // I am getting an error in this line 
}

來源

2013-03-05 10:44:35 codeMan

非法啓動類型錯誤

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